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astra-53 [7]
3 years ago
14

Determine whether each pair of segments is congruent

Mathematics
2 answers:
OLga [1]3 years ago
7 0
Set XY = XZ and solve for x
3x+5 = 5x-1
6=2x
x = 3
Then XY = 14 and XZ = 14 and YZ = 13.5
 XY congruent XZ
timurjin [86]3 years ago
5 0

Answer:

Each pair of segments is not congruent, only XY and XZ segments is congruent.

Step-by-step explanation:

Two figures are said to be <em>congruent</em> if both figures have the same shape, same dimension, they both appear the same and they both have the same angle measurement.

Thus, two segments are said to be congruent if they have same measurement.

Also, it is given in figure that,

XY = XZ

⇒ 3x + 5 = 5x - 1

⇒ 2x = 6

⇒ x = 3

Thus, XY = 3x + 5 = 3 × 3 + 5 = 14

XZ = 5x - 1 = 5 × 3 - 1 = 14

and, YZ = 9x ÷ 2 = (9 × 3 )÷ 2 = 13.5

Hence, Each pair of segments is not congruent, only XY and XZ segments is congruent.

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What is the congruence correspondence, if any, that will prove the given triangles congruent?
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<h3>HL</h3>

Step-by-step explanation:

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3 years ago
the perimeter of the circular base of a cone is 132 cm and its vertical height is 28 cm find the curved surface area total surfa
Elden [556K]

Answer:

i. Curved surface area = 2310 cm^{2}

ii. Total surface area = 3696 cm^{2}

iii. volume = 12936 cm^{3}

Step-by-step explanation:

Perimeter of the circular base = circumference of the circle = 132 cm

circumference of a circle = 2\pir

132 = 2\pir

r = \frac{132}{2\pi }

 = \frac{66}{\pi }

r = 66 x \frac{7}{22}

 = 3 x 7

 = 21

radius = 21 cm

vertical height, h = 28 cm

Thus applying the Pythagoras theorem,

l^{2} = h^{2} + r^{2}

  = 28^{2} + 21^{2}

  = 784 + 441

  = 1225

l = \sqrt{1225}

l = 35 cm

The slant height is 35 cm.

i. Curved surface area = \pirl

                           = \frac{22}{7} x 21 x 35

                           = 22 x 3 x 35

                           = 2310

curved surface area of the cone is 2310 cm^{2}.

ii. Total surface area = \pi r^{2} + \pirl

                                  = \pir(r + l)

                                  = \frac{22}{7} x 21 (21 + 35)

                                  = 22 x 3 x 56

                                  = 3696

The total surface area of the cone is 3696 cm^{2}.

iii. volume of a cone = \frac{1}{3}\pi r^{2}h

                                  =  \frac{1}{3} x \frac{22}{7} x 21^{2} x 28

                                   = 12936

The volume of the cone is 12936 cm^{3}

5 0
3 years ago
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