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MaRussiya [10]
3 years ago
6

Please help thanks :)

Mathematics
1 answer:
kykrilka [37]3 years ago
8 0
Question 1:

Multiply both sides of the proportion by 35.

You get.

7(x-1) = 4x+2

7x-7 = 4x+2

Now, add both sides by 7 and subtract both sides by 4x

3x = 9

Divide both sides by 3

x=3

Question 2:

Multiply both the numerator and the denominator of \frac{x+1}{x+3} by 3.

We want to multiply it by 3 so that the +1 and +3 become +3 and +9. +3 and +9 have a difference of 6, just like 15 and 21, which is what we want.

\frac{3x+3}{3x+9} = \frac{15}{21}

Set the numerator equal to the numerator and the denominator equal to the denominator.

3x+3 = 15

3x+9 = 21

If you solve both of these, you get x=4 for both.

That's your answer.

Hope this helps! :)
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Answer:

a_1=-10

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Step-by-step explanation:

we know that                              

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, and this constant is called the common difference (d)

In this problem we have the ordered pairs

(1,-10),(2,-7),(3,-4),(4,-1),(5,2),(6,5)                      

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a_1=-10\\a_2=-7\\a_3=-4\\a_4=-1\\a_5=2\\a_6=5

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a_2-a_1=-7-(-10)=3              

a_3-a_2=-4-(-7)=3                  

a_4-a_3=-1-(-4)=3                        

a_5-a_4=2-(-1)=3                              

a_6-a_5=5-2=3                                                        

The difference between one term and the next is a constant        

This constant is the common difference                  

so                                                                                                                                  

The sequence graphed is an Arithmetic Sequence                    

therefore                                                                                    

The first term is a_1=-10                                    

The common difference is equal to d=3          

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