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MaRussiya [10]
3 years ago
6

Please help thanks :)

Mathematics
1 answer:
kykrilka [37]3 years ago
8 0
Question 1:

Multiply both sides of the proportion by 35.

You get.

7(x-1) = 4x+2

7x-7 = 4x+2

Now, add both sides by 7 and subtract both sides by 4x

3x = 9

Divide both sides by 3

x=3

Question 2:

Multiply both the numerator and the denominator of \frac{x+1}{x+3} by 3.

We want to multiply it by 3 so that the +1 and +3 become +3 and +9. +3 and +9 have a difference of 6, just like 15 and 21, which is what we want.

\frac{3x+3}{3x+9} = \frac{15}{21}

Set the numerator equal to the numerator and the denominator equal to the denominator.

3x+3 = 15

3x+9 = 21

If you solve both of these, you get x=4 for both.

That's your answer.

Hope this helps! :)
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