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dsp73
3 years ago
6

After graphing 4x-2y=5 and y=x, in how many points do they intersect

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

1 at (2.5, 2.5)

Step-by-step explanation:

you can try graphing it on desmo

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6 0
3 years ago
Please help! I really don't understand!
Varvara68 [4.7K]
A. yes this is a statistical question. it is a statistical question because you can answer the question by collecting data.


b. some clusters are.. 3,4,5, and 6 they are clusters because they are assembled around a particular value. the peak is 6 because it is the highest number it reaches. there are no gaps in this table.



c. to calculate the average with a graph you sum the numbers then divide by the total number of values in the set. for this table you add 1+2+3+3+4+4+4+5+5+5+5+5+5 then you divide by 15.

1+2+3+3+4+4+4+5+5+5+5+5+5=51

51 ÷ 15= 3.4



3 0
3 years ago
Help me please. I kinda need it right now.!
Maru [420]

Step-by-step explanation:

Given

5y - 4 = 126(corresponding \: angles) \\ 5y = 126 + 4 \\ 5y = 130 \\ y = 130  \div 5 \\  = 26

Also given

126 + (6z + 6) = 180(angles \:  on \: a \: straight \: line) \\ 132 + 6z = 180 \\ 6z = 18 0 - 132 \\ 6z = 48 \\ z = 48 \div 6 \\  = 8

Lastly,

x = 180 - 126 \\  = 54(angles \: on \: the \: same \: straight \: line \: and \: corresponding \: angles)

6 0
2 years ago
Read 2 more answers
You want to make a picture frame for a
docker41 [41]

Answer:

i think you'll need 1 foot 6 inches of wood

Step-by-step explanation:

7 0
3 years ago
Reduced form of 2ab^2-a^2 b^2/5
Ket [755]

Answer:

2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}

Step-by-step explanation:

Given the expression

2ab^2-\frac{a^2b^2}{5}

\mathrm{Convert\:element\:to\:fraction}:\quad \:2ab^2=\frac{2ab^25}{5}

2ab^2-\frac{a^2b^2}{5}=\frac{2ab^2\cdot \:5}{5}-\frac{a^2b^2}{5}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

                 =\frac{2ab^2\cdot \:5-a^2b^2}{5}

                 =\frac{10ab^2-a^2b^2}{5}

Thus,

2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}

7 0
3 years ago
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