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4 years ago

Four times the sum of f and g is identical to six times g

Mathematics

2 answers:

Katarina [22]4 years ago

4 0

4(f+g)=6g

There in no actual solving, just plug in the quantities.

Neporo4naja [7]4 years ago

4 0

The answer is 4(fxg)=6g

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I=PRT; if P=10, R=0.1 and I=200,

brilliants [131]

10 × 0.1 × t = 200
1 × t = 200
t = 200

4 0

3 years ago

HELP QUICK ILL GIVE BRAINLIEST!!!!

gulaghasi [49]

Answer:

Step-by-step explanation:

a) circumference = diameter*pi

so, pi in circle A =25.12/8=3.14

pi in circle B = 9.42/3 =3.14

b) area of the circle =(diameter/2)^2*pi

so pi in circle A = 50.24/(8/2)^2=3.14

pi in circle B = 3.14

C) both the value of circle A and B are equivalent

4 0

3 years ago

For every line there can exist a coplanar parallel line. true or false?

julsineya [31]

Answer:

Step-by-step explanation:

7 0

3 years ago

3x+9=1x what’s the slope and intercept form

tresset_1 [31]

Answer:

this equation cannot be written in slope-intercept form

Step-by-step explanation:

The given equation is equivalent to ...

2x +9 = 0 . . . . . subtract 1x

x + 4.5 = 0 . . . . divide by 2

x = -4.5 . . . . . . . the equation of a vertical line.

It has no y-intercept and its slope is undefined.

5 0

3 years ago

Write a quadratic equation in standard form that has a vertex of (-2, 6) and passes through (-4, -2).

Marizza181 [45]

Answer:

The equation of the quadratic in standard form is:

$y=-2x^2-8x-2$

Step-by-step explanation:

Since they give us the information about where the vertex of the parabola is located, and one extra points where it passes through, we can use the general form of a quadratic in vertex form:

$y-y_v=a\,(x-x_v)^2$

where $(x_v,y_v)$ is the location of the vertex (in our case the point (-2,6).

Therefore the equation above becomes:

$y-y_v=a\,(x-x_v)^2\\y-6=a\,(x-(-2))^2\\y-6=a\,(x+2)^2$

Now,we can use the fact that the point (-4,-2) is also a point of the graph, to find the value of the parameter $"a"$ :

$y-6=a\,(x+2)^2\\-2-6=a\,(-4+2)^2\\-8=a\,(-2)^2\\-8=a\,*4\\a=-2$

Then, the equation of the quadratic with such characteristics becomes:

$y-6=-2\,(x+2)^2\\y-6=-2x^2-8x-8\\y=-2x^2-8x-2$

which is the equation of the quadratic in standard form.

7 0

3 years ago