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Zinaida [17]
3 years ago
15

10.........................

Mathematics
1 answer:
alukav5142 [94]3 years ago
5 0
<h2>Hello!</h2>

The answer is:

a. a^{\frac{3}{2}}bc^{2}

<h2>Why?</h2>

To simplify the expression, we need to transform the radical into a exponential form, then apply the exponential property.

Transforming radical to exponential form:

\sqrt[n]{x}=x^{\frac{1}{n}}\\\sqrt{x}=x^{\frac{1}{2} }

Power of a power property:

(a^{m})^{n}=a^{mn}\\\\(a^{m})^{\frac{1}{n}}=a^{\frac{m}{n}}

So,

\sqrt[4]{a^{6}b^{4}c^{8}}=(a^{6}b^{4}c^{8})^{\frac{1}{4}}\\\\(a^{6}b^{4}c^{8})^{\frac{1}{4}}=a^{\frac{6}{4}}b^{\frac{4}{4}}c^{\frac{8}{4}}\\\\a^{\frac{6}{4}}b^{\frac{4}{4}}c^{\frac{8}{4}}=a^{\frac{3}{2}}bc^{2}

Have a nice day!

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A cell phone and phone case cost $110 in total. The cell phone costs $100 more
Olegator [25]

Answer:

Step-by-step explanation:

p + c = 110

p = c + 100

c + 100 + c = 110

2c + 100 = 110

2c = 110 - 100

2c = 10

c = 10/2

c = 5 .......cost of the phone case

p = c + 100

p = 5 + 100

p = 105 <=== cost of the phone

3 0
4 years ago
How do you multiply fractions and express product in simplestform.
vagabundo [1.1K]
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3 years ago
Approximate f by a Taylor polynomial with degree n at the number a. Step 1 The Taylor polynomial with degree n = 3 is T3(x) = f(
MAVERICK [17]

Answer:

If you center the series at x=1

T_3(x) = e^2 + 4e^2 (x-1)+10(x-1)^2 + \frac{56}{3} e^2(x-1)^3 + R(x)

Where R(x) is the error.

Step-by-step explanation:

From the information given we know that

f(x) = e^{2x^2}

f'(x) = 4x e^{2x^2}   (This comes from the chain rule )

f^{(2)}(x) = 4e^{2x^2} (4x^2+1)   (This comes from the chain rule and the product rule)

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If you center the series at x=1  then

T_3(x) = e^2 + 4e^2 (x-1)+10(x-1)^2 + \frac{56}{3} e^2(x-1)^3 + R(x)

Where R(x) is the error.

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How many dimes would you need to make $90.10
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Hope this helps
3 0
3 years ago
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