What would you use to represent the solution in an equation with a variable?
I would use the real line that goes from x belongs (-infinite, infinite).
What would you use to represent the solution in an equation with three variables?
To present the solution of an equation with three variables you need the XYZ coordinate system because you would generate a 3D graph because "because the number of variables is equal to the number of dimensions needed to graph the solution correctly".
Could you graph an equation that contains more than four variables?
It CAN NOT be done since the number of variables is equal to the number of dimensions that are needed to graph the solution correctly. Therefore, we can graph only up to three variables (three dimensions).
If you were given the graph of an equation with two variables in a coordinate plane, what would happen to the graph if all the values of y were increased by 1?
if all the values of y are increased by 1, the graph shifts by 1 unit to the right.
What would happen to the graph if all values of x were increased by 1?
If all values of x are increased by 1, the graph moves 1 unit up.
What would happen to the graph if all the <span> y-</span>values were multiplied by 2 or by 1/2?
If the values of y are multiplied by 1/2 then the slope of the graph is smaller so the graph looks wider.
If the values of y are multiplied by 2 then the slope of the graph is larger so the graph looks narrower.
Answer:
No. He is short by 2 minutes
Step-by-step explanation:
Given that Denzel can mow 1/8 of his yard every 7 minutes.
Hence he can mow the full yard in 7(8) = 56 minutes.
Now he has to do 3/4 of his yard and time is 40 minutes
For 3/4 of yard time taken would be = 3/4 (56) = 42 minutes.
If he had 40 minutes to mow 3/4 of the yard, he will not have enough time since he is short of time by 2 minutes.
Answer:
(x, y) = (4,-3)
Step-by-step explanation:
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Answer:
The answer is \frac{2A}{h} -b_2=b_1
Step-by-step explanation:
Given that the area of a trapezoid is ;
A=1/2 (b₁+b₂)h
When the equation is solved for b₁ it will be;
A=1/2 (b₁+b₂)h
This can be written as;
A=h/2 (b₁+b₂)
Multiply both sides by 2/h
2A/h = b₁+b₂
Make b₁ subject of the formula
2A/h - b₂ = b₁
I think you meant to say

(as opposed to <em>x</em> approaching 2)
Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:
