All methods are supposed to be correct in most if not all situations and it should not matter if you use a different method given the options
Answer:
a. 2^3
b. 3^4
c. 4^3 × 5^2
d. 9^4 × 7^2
Step-by-step explanation:
The following equations are given
a. 2 × 2× 2
b. 3 × 3 × 3 × 3
c. 4 × 4 × 4 × 5 × 5
d. 9 × 7 × 9 × 9 × 7 × 9
We need to find the index notation for the above equations
a. 2^3
b. 3^4
c. 4^3 × 5^2
d. 9^4 × 7^2
In this way it should be done
The same would be relevant
Let x = no. of 10 oz cups sold
Let y = no. of 14 oz cups sold
Let z = no. of 20 oz cups sold
:
Equation 1: total number of cups sold:
x + y + z = 24
:
Equation 2: amt of coffee consumed:
10x + 14y + 20z = 384
:
Equation 3: total revenue from cups sold
.95x + 1.15y + 1.50z = 30.60
:
Mult the 1st equation by 20 and subtract the 2nd equation from it:
20x + 20y + 20z = 480
10x + 14y + 20z = 384
------------------------ subtracting eliminates z
10x + 6y = 96; (eq 4)
Mult the 1st equation by 1.5 and subtract the 3rd equation from it:
1.5x + 1.5y + 1.5z = 36.00
.95x + 1.15y+ 1.5z = 30.60
---------------------------subtracting eliminates z again
.55x + .35y = 5.40; (eq 5)
Multiply eq 4 by .055 and subtract from eq 5:
.55x + .35y = 5.40
.55x + .33y = 5.28
--------------------eliminates x
0x + .02y = .12
y = .12/.02
y = 6 ea 14 oz cups sold
Substitute 6 for y for in eq 4
10x + 6(6) = 96
10x = 96 - 36
x = 60/10
x = 6 ea 10 oz cups
That would leave 12 ea 20 oz cups (24 - 6 - 6 = 12)
Check our solutions in eq 2:
10(6) + 14(6) + 20(12) =
60 + 84 + 240 = 384 oz
A lot steps, hope it made some sense! I hope this helps!! ;D
Answer:
The sales price is 90% of the regular price.
The regular price is $60
10% of 60 is $6
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