Answer:
Specific heat capacity formula
Explanation:
The heat capacity gives the exact heat energy at which a given mass of a substance is heated from one temperature to another.
This formula can help determine how much heat is gained or lost during the reaction and is given by:
Q = mcΔT
where:
Q = heat energy in Joules or Calories
m - mass of the substance (g)
c = Specific heat capacity (J/kg°C)
ΔT = change in temperature = (final temp - initial temp) (°C)
I hope this was helpful.
Divide 180kg and 90m3 and your density will be 2kg/m3
Answer:
The final temperature of the water mixture is 47.85°C
Explanation :
Given,
For Warm Water
mass = 10grams
Temperature = 105°C
For Cold Water
mass = 25grams
Temperature = 25°C
When a sample of warm water is mixed with a sample of cool water,
The energy amount going out of the warm water is equal to the energy amount going into the cool water. This means:
<h3>Qlost = Qgain</h3>
However,
Q = (mass) (ΔT) (Cp)
Cp = Specific heat of water = 4.184 J/Kg°C
So,
(mass) (ΔT) (Cp) = (mass) (ΔT) (Cp)
We start by calling the final, ending temperature 'x.' Keep in mind that BOTH water samples will wind up at the temperature we are calling 'x.' Also, make sure you understand that the 'x' we are using is FINAL temperature. This is what we are solving for.
The warmer water goes down from to 105°C to x, so this means its Δt equals 105°C − x. The colder water goes up in temperature, so its Δt equals x − 25℃
Substituting the values,
(10)( 105°C − x)(4.184) = (25)(x − 25℃)(4.184)
Solving for x, we get
x = 47.85°C
Therefore, The final temperature of the water mixture is 47.85°C.
I believe the answer is carbon dioxide. Because when carbon dioxide and water combine in the atmosphere it forms a very weak acid called carbonic acid, which falls to the Earth's surface as precipitation.