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Annette [7]
3 years ago
7

The image shows a molecular model of a compound using balls and sticks. Each ball is an atom and each stick is a bond. If you we

re to use balls
and sticks to model a molecule of an element, how must your model differ from what's shown?​

Chemistry
1 answer:
jeka943 years ago
7 0
<h2><u>Full Question:</u></h2>

The image shows a molecular model of a compound using balls and sticks. Each ball is an atom and each stick is a bond. If you were to use balls and sticks to model a molecule of an element, how must your model differ from what’s shown?

A. The sticks must be shorter.

B. The balls must be the same color.

C. The balls must be smaller.

D. The balls must change to cubes.

<h2><u>Answer:</u></h2>

The balls must be of same colour.

Option B.

<h3><u>Explanation:</u></h3>

A Molecule is defined as the smallest part of an element or compound which can exist freely in nature. An element is define as the matter which is when divided into smallest particles gives only one type of particle or atom. Where as a compound is defined as the combination of different elements in a particular ratio which has properties totally different from the combining elements. So an element comprises of only one type of atoms.

In this picture we can see that there is a central atom which is marked in blue where as the other atoms are peripheral and marked in red. The bonds between the blue atom and red atoms are marked with sticks. So if only one type of atoms are present in the molecule then only one coloured balls will be seen. Then the the colour of the balls will be only one.

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3 years ago
If you had 6H2 molecules and 4O2 molecules, how many H2O molecules could you produce?
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A student ran the following reaction in the laboratory at 311 K:CH4(g) + CCl4(g) 2CH2Cl2(g)When she introduced 4.10×10-2 moles o
statuscvo [17]

<u>Answer:</u> The value of K_{eq} is 0.044

<u>Explanation:</u>

We are given:

Initial moles of methane = 4.10\times 10^{-2}mol=0.0410moles

Initial moles of carbon tetrachloride = 6.51\times 10^{-2}mol=0.0651moles

Volume of the container = 1.00 L

Concentration of a substance is calculated by:

\text{Concentration}=\frac{\text{Number of moles}}{\text{Volume}}

So, concentration of methane = \frac{0.0410}{1.00}=0.0410M

Concentration of carbon tetrachloride = \frac{0.0651}{1.00}=0.0651M

The given chemical equation follows:

                    CH_4(g)+CCl_4(g)\rightleftharpoons 2CH_2Cl_2(g)

<u>Initial:</u>          0.0410    0.0651

<u>At eqllm:</u>     0.0410-x   0.0651-x       2x

We are given:

Equilibrium concentration of carbon tetrachloride = 6.02\times 10^{-2}M=0.0602M

Evaluating the value of 'x', we get:

\Rightarrow (0.0651-x)=0.0602\\\\\Rightarrow x=0.0049M

Now, equilibrium concentration of methane = 0.0410-x=[0.0410-0.0049]=0.0361M

Equilibrium concentration of CH_2Cl_2=2x=[2\times 0.0049]=0.0098M

The expression of K_{eq} for the above reaction follows:

K_{eq}=\frac{[CH_2Cl_2]^2}{[CH_4]\times [CCl_4]}

Putting values in above expression, we get:

K_{eq}=\frac{(0.0098)^2}{0.0361\times 0.0603}\\\\K_{eq}=0.044

Hence, the value of K_{eq} is 0.044

8 0
3 years ago
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