Answer:
(1) Cl₂ is the limiting reactant.
(2) 8.18 g
Explanation:
- 2Na(s) + Cl₂(g) → 2NaCl(s)
First we <u>convert the given masses of reactants into moles</u>, using their <em>respective molar masses</em>:
- Na ⇒ 12.0 g ÷ 23 g/mol = 0.522 mol Na
- Cl₂ ⇒ 5.00 g ÷ 70.9 g/mol = 0.070 mol Cl₂
0.070 moles of Cl₂ would react completely with (2 * 0.070) 0.14 moles of Na. There are more Na moles than that, so Na is the reactant in excess while Cl₂ is the limiting reactant.
Then we <u>calculate how many moles of NaCl are formed</u>, <em>using the limiting reactant</em>:
- 0.070 mol Cl₂ *
= 0.14 mol NaCl
Finally we <u>convert NaCl moles into grams</u>:
- 0.14 mol NaCl * 58.44 g/mol = 8.18 g
K has the lowest and Br has the higher
Ok, I will help you answer but it is very hard to read could you enlarge it first?
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The question is missing the graphics required to answer which I have attached as an image.
There are four different representations of the orientation of water molecules around chloride anion. Let's first analyze the water molecule.
We have H-O-H as the structure of water. The oxygen atom is more electronegative than the hydrogen atoms, which results in a partial positive charge on the hydrogen atoms and a partial negative charge on the oxygen atom.
The chloride anion is a negative charge. Therefore, the water molecules should orient themselves with the hydrogen atoms facing the chlorine atom as the partial positive charge on the hydrogen atoms will be attracted to the negative charge of the chlorine atom.
The correct representation is shown in graph 3 which shows all hydrogen atoms facing the chlorine anion.
Answer: The pull of the moon's gravity on Earth's water causes tidal bulges to form on the side closest to the moon and farthest from the moon. In the place where there are tidal bulges, high tide occurs along coastline.
Explanation:
