637,980 Joules is needed to raise the temperature of 2.50 kg of this oil from 23 ∘C to 191 ∘C.
<h3>What is specific heat?</h3>
The heat in calories required to raise the temperature of one gram of a substance one degree Celsius.
Q = cmΔT
where
Q = heat energy needed for that material to get desired temperature change (in Joules)
M = mass (in grams) so you have to convert from kilograms.
c = specific heat constant for the material being heated
ΔT = change in temperature
Q = (1.75)(2.17 x 1000)(191 - 23)
Q = (1.75)(2170)(168)
Q = 637,980 Joules
Hence, 637,980 Joules is needed to raise the temperature of 2.50 kg of this oil from 23 ∘C to 191 ∘C.
Learn more about the specific heat capacity here:
brainly.com/question/9560546
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Low density. Makes it light and able to bet in the air.
Answer:
The reactants in this equation is HgO.
Explanation:
The reactants are the substances to the left of the arrow (equal sign) in an equation.
Low temperature! since there are less molecules with energy greater than activation energy and they posses less energy to collide with each other and change into products.