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Elan Coil [88]
3 years ago
15

2 sin x cos x – sin x = 0

Mathematics
1 answer:
solniwko [45]3 years ago
7 0

Answer: PiN, Pi/3+2PiN, 5Pi/3+2PiN

Step-by-step explanation: Use formula sheet

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STUDENT HOURS KATY 5.5
mario62 [17]
The best answer to go with is b
4 0
3 years ago
P(vanilla) =0.3 P(sundae)=0.2 P(vanilla and sundae) =0.15 find the probability that a customer ordered vanilla ice cream given t
Art [367]

Answer:

0.75

Step-by-step explanation:

P(A | B) = P(A and B) / P(B)

P(vanilla | sundae) = P(vanilla and sundae) / P(sundae)

P(vanilla | sundae) = 0.15 / 0.2

P(vanilla | sundae) = 0.75

6 0
3 years ago
Suppose that some country had an adult population of about 50 million, a labor-force participation rate of 60 percent, and an un
schepotkina [342]

Answer:

The Answer is b. 1.5Million

Step-by-step explanation:

Adult Population = 50 Million

Labor-Force Rate = 60%

Total Labor Force of Adult population = 50Million*60% = 30Million

Unemployment Rate = 5%

People Unemployment =

Total Labor force of Adult population * Unemployment rate

People Unemployment = 30Millon*5%

People Unemployment = 1.5Million

8 0
3 years ago
How many solutions does this system have? -6x + 18y = 264. - 12x - 36y = 130 . PLS HELP​ ill give brainliest
Alchen [17]

Answer:

x=−44 + 3y

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Step-by-step explanation:

plz mark brainliest

8 0
2 years ago
In a certain Algebra 2 class of 27 students, 11 of them play basketball and 9 of them play baseball. There are 11 students who p
grigory [225]
<h2>Answer:</h2><h2>The probability of students who play both basketball and baseball =  \frac{4}{27}</h2>

Step-by-step explanation:

In a certain Algebra class,

The total number of students = 27 students

Let the students playing basketball be represented as A and baseball as B.

The students who play basketball, A= 11

The students who play basetball,B =9

The students who play neither sport,  = 11

The students who play both basketball and baseball,  = ?

By formula, P(AUB)=P(A)+P(B)-P(A∩B)

Substituting the values in the equation, we get

P(AUB) = \frac{11}{27} + \frac{9}{27} - \frac{16}{27}

 P(AUB) = \frac{4}{27}

The probability of students who play both basketball and baseball =  \frac{4}{27}

8 0
3 years ago
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