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diamong [38]
3 years ago
7

What’s the equation of the midline?

Mathematics
2 answers:
ycow [4]3 years ago
5 0

Answer:

Midline: y = 0

Equation: y = -cos(2x)

vazorg [7]3 years ago
4 0

Answer:

This graph is the equation of -cosx

Step-by-step explanation:

This is a cosine graph that has been flipped across the x-axis producing a          -cosx.

Answer:  This graph is the equation of -cosx

<u>Graph Below:</u>

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Write each expression as a product of linear factors 1. X^2+1/2x 2. X^2+2x-3 3. (2x-3)^2 4. X^3+2x^2-19x-20
Grace [21]

Answer:

1. X^2+1/2x = x(x+\frac{1}{2})

2.  X^2+2x-3 = (x-1)(x+3)

3. (2x-3)^2 = (2x-3)(2x-3)

4. X^3+2x^2-19x-20 = (x+1)(x-4)(x+5)

Step-by-step explanation:

Each expression can be written as a product of linear factors as follows

1. X^2+1/2x ⇒ x^{2} + \frac{1}{2}x

x^{2} + \frac{1}{2}x = x(x+\frac{1}{2})

Hence,  X^2+1/2x = x(x+\frac{1}{2})

2. X^2+2x-3 ⇒ x^{2} +2x-3

x^{2} +2x-3 = x^{2} +3x-x-3

x^{2} +3x-x-3 = x(x+3) -1(x+3)

x(x+3) -1(x+3) = (x-1)(x+3)

Hence,  X^2+2x-3 = (x-1)(x+3)

3. (2x-3)^2 ⇒(2x-3)^{2}

(2x-3)^{2} = (2x-3)(2x-3)

Hence, (2x-3)^2 = (2x-3)(2x-3)

4. X^3+2x^2-19x-20 ⇒ x^{3}+2x^{2} -19x -20

x^{3}+2x^{2} -19x -20  = (x+1)(x^{2} +x-20)

First,

x^{2} +x-20 = x^{2} +5x-4x-20\\x^{2} +5x-4x-20= x(x+5)-4(x+5)\\x(x+5)-4(x+5) = (x-4)(x+5)

∴ (x+1)(x^{2} +x-20) = (x+1)(x-4)(x+5)

Hence, X^3+2x^2-19x-20 = (x+1)(x-4)(x+5)

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