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eimsori [14]
3 years ago
11

Figure 1 is dilated to get Figure 2. What is the scale factor?

Mathematics
1 answer:
aivan3 [116]3 years ago
4 0
It’s 4:9 or 4/9 because you do 8:18 then reduce it (in this case divide by two, the greatest common factor) and get 4:9
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How many times greater is the 6 in 6,275 than the 6 in 62.75?
prohojiy [21]

Answer:

B. 10

Step-by-step explanation:

{ \tt{(6 \times 6.275)n = (6 \times 62.75)}} \\ { \tt{6.275n = 62.75}} \\ { \tt{n = 10}}

6 0
2 years ago
Your friend grace needs help to find the values of x,y and z in the figure below
kow [346]

Answers:

x = 57

y = 86

z = 37

=================================================

Work Shown:

x+123 = 180 .... since x and 123 form a straight line

x = 180-123

x = 57

y = 86 since the y and 86 angles are vertical angles

-------

For any triangle, the three angles always add to 180. So,

x+y+z = 180

57+86+z = 180

143+z = 180

z = 180-143

z = 37

As a check,

x+y+z = 57+86+37 = 180

which confirms the value of z

5 0
4 years ago
What is the value of |−32|?
kolezko [41]

Answer:

32

Step-by-step explanation:

|-32|

Absolute values means take the positive value of

|-32| = 32

7 0
3 years ago
Read 2 more answers
The function d(t) =300,000t represents the distance (in kilometers) that light travels in t seconds
3241004551 [841]

We were given the distance, d as a function of time, t.

d(t)=300,000t.

To find d(15), we put t=15, in to


d(t)=300,000t


This implies that,

d(15)=300,000(15)


d(15)=4,500,000

This means that in 15 seconds light covers a distance of 4,500,000 kilometers

5 0
3 years ago
Read 2 more answers
PLEASE HELP ME THIS IS DUE TOMMAROW!!!!
Y_Kistochka [10]

Answer:

4. $130.50

Step-by-step explanation:

Sorry, but I only know for no.4 which is $130.50.

Explanation: 18 hours is 20 percent more than 15 hours.


So all we have to do is multiply 1.2 to 108.75, since multiplying 1.2 is the equivalent to 20 percent.

Which then is why I get the answer of $130.50.


If that helped please hit Thank button!

4 0
3 years ago
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