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3 years ago

6

Which expression is equivalent to (7^-8)(7^3)

1 answer:

suter [353]3 years ago

7 0

Answer:

1/16807

Step-by-step explanation:

(7^-8)(7^3)=7^(-8+3)=7^-5=1/7^5=1/16807

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4 x4 +5 x 3=31== estimate 30$

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2 years ago

Find sin 2x,cos2x and tan2x,if tanx=-(3)/(4)and x terminates in quadrant IV

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Answer:PLEASE HELP ME

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Carl is standing at the base of a zip line which is 400 ft away from the base of the building that is connected to the top of a building. Standing 5.5 ft tall, he looks up to the top of the building at an angle of elevation of 25 degrees. A weight is released and travels down the zip line to his feet. How far did the weight travel? Round to nearest 10th of a foot and do not use units in your answer.

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2 years ago

What equation is represented by the equation on the graph ?

solmaris [256]

Answer: The correct option is D.

Explanation:

From the graph we noticed that the x intercept of the line is (2,0) and the y-intercept is (0,2).

If the line passing through two points then the equation of line is,

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

Since the ien passing through (2,0) and (0,2).

$y-0=\frac{2-0}{0-2}(x-2)$

$y=-1(x-2)$

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This equation is represented by option D, therefore the option D is correct.

6 0

3 years ago

X/3 = 2,how to calculate x? <br> please help me

liq [111]

Given:

$\sf \dfrac{x}{3} = 2$

Solution:

$\longrightarrow \sf \dfrac{x}{3} = 2 \\ \\ \sf\longrightarrow x = 3 \times 2 \\ \\ \longrightarrow {\underline{\boxed{ \pink {\sf{x = 6}}} }}\\ \\$

4 0

2 years ago

Read 2 more answers

Assume the time required to complete a product is normally distributed with a mean 3.2 hours and standard deviation .4 hours. Ho

Alex787 [66]

Answer: 3.712 hours or more

Step-by-step explanation:

Let X be the random variable that denotes the time required to complete a product.

X is normally distributed.

$X\sim N(\mu=3.2\text{ hours},\ \sigma=0.4\text{ hours} )$

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

Then, $P(\dfrac{X-\mu}{\sigma}>\dfrac{x-\mu}{\sigma})=0.10$

$P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]$

As, $P(z>1.28)=0.10$ [By z-table]

Then,

$\dfrac{x-3.2}{0.4}=1.28\\\\\Rightarrow\ x=0.4\times1.28+3.2\\\\\Rightarrow\ x=3.712$

So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

3 0

3 years ago