Answer:
Rational form:
399/100 = 3 + 99/100
Continued fraction:
[3; 1, 99]
Possible closed forms:
399/100 = 3.99
log(54)≈3.988984
8/(3 π) + π≈3.9904190
1/2 (e! + 1 + e)≈3.989551
-(sqrt(3) - 3) π≈3.983379
(14 π)/11≈3.9983906
25/(2 π)≈3.978873
(81 π)/64≈3.976078
(2 e^2)/(1 + e)≈3.974446
(π π! + 2 + π + π^2)/(3 π)≈3.988765
2 π - log(4) - 3 log(π) + 2 tan^(-1)(π)≈3.987955
2 - 1/(3 π) + (2 π)/3≈3.988291
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
The answer is D
hope this helps :)
Answer:
y=11x-18
Step-by-step explanation:
y=11x+b (b is the unknown y-int)
to find the y-int, substitute in (2, 4), and solve for b *substitute in 2 for x and 4 for y*
y=11x+b
4=11(2)+b
4=22+b
b=-18
the equation of the line:
y=11x-18
Answer:
y = 3z - 2x
Step-by-step explanation:
Systems of equations can be solved by a number of know techniques, such as substitution, elimination or graphical approach.
We are required to solve the system of equations given via substitution;
2x + y = 3z
x + y = 6z
The question requires us to determine the value for y from the first equation, that could be substituted into the second equation.
We simply need to make y the subject of the formula from the first equation;
2x + y = 3z
To do this we subtract 2x on both sides of the equation;
2x + y -2x = 3z - 2x
y = 3z - 2x
This is the value of y from the first equation, that can be substituted into the second equation.
