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Mrrafil [7]
3 years ago
10

The last time David filled up his truck with gas, he paid $27.44 for 7 gallons. This time, he needs 15 gallons. If the price is

the same, how much will he pay?
Mathematics
1 answer:
Tema [17]3 years ago
7 0
The last time David filled up his truck with gas, he paid $27.44 for 7 gallons. This time, he needs 15 gallons. If the price is the same, how much will he pay?
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__________________________________________
xz_007 [3.2K]

Answer:

3.3 x 10⁻⁴

Step-by-step explanation:

Given expression:

           \frac{2.64 x 10^{-3} }{8.0 x 10^{0} }

 To solve this problem;

    10°   = 1

So;

             \frac{2.64 x 10^{-3} }{8.0}

    =  \frac{2.64}{8}  x 10⁻³

    = 0.33 x 10⁻³

    = 3.3 x 10⁻¹  x 10⁻³

     = 3.3 x 10⁻⁴

4 0
2 years ago
Write a system of equations to represent the scenario.
Nookie1986 [14]

Answer:

Step-by-step explanation:I need the same answer lol

4 0
2 years ago
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Rationalize the denominator and simplify.<br> 6<br> 15 - 3
Rzqust [24]

Answer:

a)6 =  \frac{6}{1} = 6  \:  \:  \: b)15 - 3 =  \frac{15}{3} = 5

5 0
2 years ago
What is the volume of the right prism with height h=14 cm, if the base of the prism is a triangle ∆ABC with side AB = 9 cm and a
LenaWriter [7]

Answer:

378

Step-by-step explanation:

9*6=54 then 54/2=27. fnally 27*14=378

6 0
3 years ago
Read 2 more answers
Which of the following is not equal to sin⁡(-230°)?
xenn [34]

From trigonometry we know that:

if sin(\theta)=sin(\alpha)

then, \theta=n\pi+(-1)^n\alpha (where n is an integer)

This can be rewritten in degrees as:

\theta=n(180^{\circ})+(-1)^n\alpha.............(Equation 1)

Now, in our case, \alpha=-230^{\circ}

Therefore, (Equation 1) can be written as:

\theta=n(180^{\circ})+(-1)^n(-230^{\circ})..........(Equation 2)

Now, to find the correct options all that we have to do is replace n by relevant integers and find the values of \theta that match.

For n=2, (Equation 2) gives us: \theta=2\times 180^{\circ}+(-1)^2(-230^{\circ})=360^{\circ}-230^{\circ}=130^{\circ}.

Thus, sin(230^{\circ})=sin(130^{\circ})

Now, we know that: -sin(-50^{\circ})=sin(50^{\circ})

Let n=-1, then:

\theta=(-1)\times 180^{\circ}+(-1)^{-1}(-230^{\circ})=-180^{\circ}+230^{\circ}=50^{\circ}

Thus, sin(-230^{\circ})=-sin(-50^{\circ})

Likewise, sin(-230^{\circ})=sin(50^{\circ})

Only the last option sin(-50^{\circ}) will never match sin(-230^{\circ}) because no integral value of n will ever give \theta=-50^{\circ}

Thus the last option is the correct option.

3 0
2 years ago
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