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3 years ago

Can somebody please show me how to do this problem

Mathematics

1 answer:

tia_tia [17]3 years ago

8 0

Answer:

g(20) > f(20)
g(x) exceeds f(x) for any x > 4

Step-by-step explanation:

As with most graphing problems not involving straight lines, it works well to start with a table of values. Pick a few values of x and compute f(x) and g(x) for those values. Plot the points and draw a smooth curve through them.

As in the attached, your table will show that there are two points of intersection between f(x) and g(x), and that for values of x more than 4, g(x) becomes much greater very quickly. Both curves rapidly reach the top of your graph space.

To find whether f(20) or g(20) is greater, you can evaluate the functions for that value of x.

f(20) = 20² = 400

g(20) = 2²⁰ = 1,048,576

Clearly, g(20) has a greater value.

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Two assembly lines I and II have the same rate of defectives in their production of voltage regulators. Six regulators are sampl

Kamila [148]

Answer:

0.4546

Step-by-step explanation:

nCr = n!/(n-r)!r!

Number of ways of selecting the four defective voltage regulators from 12 = 12C4 = 12!/(12-4)!4! = 12!/8!4! = (12 *11*10*9)/(4*3*2*1)

12C4 = 495 ways

Number of ways of selecting 2 defectives from line 1 = 6C2 * 6C2

6C2 = 6!/(6-2)!2! = 6!/4!2! = (6*5)/(2*1) = 15

6C2 * 6C2 = 15*15 = 225 ways

Probability = Number of possible outcomes/ Number of total outcomes

Probability that exactly 2 of the defective regulators came from line 1 = 225/40.95 = 0.4546

4 0

3 years ago

HELP HELP HELP HELP HELP

Harman [31]

B
I need 20 characters lol

8 0

3 years ago

Read 2 more answers

Please help! Thank you!

KIM [24]

The correct answer is: [B]: " (2, 5) ".
__________________________________________
Given:
__________________________________________
-5x + y = -5 ;
  -4x + 2y = 2 .
___________________________________________
Consider the first equation:
___________________________
-5x + y = -5 ; ↔ y + (-5x) = -5 ;

↔ y - 5x = -5 ; Add "5x" to each side of the equation; to isolate "y" on one side of the equation; and to solve in terms of "y".
_____________________________________________
   y - 5x + 5x = -5 + 5x

   y = -5 + 5x ; ↔ y = 5x - 5 ;
____________________________________________
Now, take our second equation:
______________________________
     -4x + 2y = 2 ; and plug in "(5x - 5)" for "y" ; and solve for "x" :
_____________________________________________________
         -4x + 2(5x - 5) = 2 ;
______________________________________________________
Note, 2(5x - 5) = 2(5x) - 2(5) = 10x - 10 ;
__________________________________________
So:   -4x + 10x - 10 = 2 ;

On the left-hand side of the equation, combine the "like terms" ;

-4x +10x = 6x ; and rewrite:

6x - 10 = 2 ;

Now, add "10" to each side of the equation:

6x - 10 + 10 = 2 + 10 ;

to get:

           6x = 12 ; Now, divide EACH side of the equation by "6" ; to isolate "x" on one side of the equation; and to solve for "x" ;

           6x/6 = 12 / 6 ;

                 x = 2 ;
_________________________________
Now, take our first given equation; and plug our solved value for "x" ; which is "2" ; and solve for "y" ;
_____________________________________
-5x + y = -5 ;

-5(2) + y = -5 ;

-10 + y = -5 ; ↔
                              y - 10 = -5 ;

Add "10" to each side of the equation; to isolate "y" on one side of the equation; and to solve for "y" ;

         y - 10 + 10 = -5 + 10 ;

                   y = 5 .
_____________________________
So, we have, x = 2 ; and y = 5 .
____________________________
Now, let us check our work by plugging in "2" for "x" and "5" for "y" in BOTH the original first and second equations:
______________________________
first equation:

-5x + y = -5 ;

-5(2) + 5 =? -5?

-10 + 5 =? -5 ? YES!
______________________
second equation:

-4x + 2y = 2 ;

-4(2) + 2(5) =? 2 ?

-8 + 10 =? 2 ? Yes!
_______________________________________________________
So, the answer is:
___________________________________________________________
          x = 2 , y = 5 ; or, "(2, 5)" ; which is: "Answer choice: [B] " .
___________________________________________________________

3 0

3 years ago

What is the GCF of 28a^3 b and 16ab ? A)4ab B)4a3b C)28ab D)112a3b2

N76 [4]

28a⁴b: 2 · 2 · 7 · a · a · a · a · b
16ab: 2 · 2 · 2 · 2 · a · b

GCF(28a⁴b, 16ab) = 4ab

The answer is A.

7 0

3 years ago

Given triangle ABC with sides AB = 3x + 4 , BC = 2x + 5 , and AC = 4x , determine the values of x such that triangle ABC exists

Jlenok [28]

Answer:

x > 1/5

Step-by-step explanation:

All of these three triangle inequalities must be satisfied:

AB +BC > AC

BC +CA > BA

CA +AB > CB

___

Taking these one at a time, we have ...

AB +BC > AC

3x +4 + 2x +5 > 4x

x +9 > 0 . . . . . subtract 4x

x > -9

BC +CA > BA

2x +5 + 4x > 3x +4

3x > -1 . . . . . . subtract 3x+5

x > -1/3 . . . . . divide by 3

CA + AB > CB

4x + 3x +4 > 2x +5

5x > 1 . . . . . . subtract 2x+4

x > 1/5

___

The only values of x that satisfy all of these inequalities are those such that ...

x > 1/5

8 0

3 years ago