Answer:
20
Step-by-step explanation:
<u>15</u> = <u>75</u>
x 100 (then cross multiply below)
---------------------------
<u>1,500</u> = <u>75x </u>
75 75
20 = x
For a chad drives 56 miles per hour. you got this by dividing 168 by 3.
for b it takes chad 12 hours and you got this by dividing 672 by 56.
for c, chads car gets 28 miles per gallon you got this by dividing 308 by 11
for d, chads car uses uses 24 gallons to travel 672 miles an you got this by dividing 672 by 28. hope this is right.:)
9514 1404 393
Answer:
r ≈ 19.0
s ≈ 17.7
Step-by-step explanation:
The relevant trig relations are ...
Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse
So, you have ...
cos(43°) = r/26
r = 26·cos(43°) ≈ 19.0
__
sin(43°) = s/26
s = 26·sin(43°) ≈ 17.7
Answer:
the chemist should use 60 liters of 55% solution and 40 litres of 30% solution in order to prepare 100 liters of 45% purity of sulphuric acid.
Step-by-step explanation:
From the given information,
Let x be the litres of 55% pure solution
Let y be the litres of 30% pure solution
Also;
Given that our total volume of solution is 100 litres
x+y =100 ---- (1)
The total solution of pure by related by the sum of the individual pure concentrations to make up the concentration of final solution.
(0.55)(x)+(0.30)(y) = 0.45(100) ---- (2)
From equation (1)
Let ; y = 100 - x
Replacing the value for y = 100 - x into equation (2)
(0.55)(x)+(0.30)(100-x) = 0.45(100)
0.55x + 30 - 0.30x = 45
0.55x - 0.30x = 45 - 30
0.25x = 15
x = 15/0.25
x = 60 liters of 55% solution
From ; y = 100 - x
y = 100 - 60
y = 40 litres of 30% solution.
Therefore, the chemist should use 60 liters of 55% solution and 40 litres of 30% solution in order to prepare 100 liters of 45% purity of sulphuric acid.
Since the whole number here would be 100 all you would need to do is take 950/100 so you can take 9 whole buckets out wich is 900 so that leave you with 50 and that's half of 100 so the answer would be 9 and one half
