For each value of y, determine whether it is a solution to 7=y÷4.

A research center claims that at least 4545% of adults in a certain country think the government is not aggressive enough in pu

frez [133]

Answer:

$z=\frac{0.39 -0.45}{\sqrt{\frac{0.45(1-0.45)}{700}}}=-3.19$

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interst is significantly lower than 0.45 and the claim is not appropiate

Step-by-step explanation:

Data given and notation

n=700 represent the random sample taken

$\hat p=0.39$ estimated proportion of interest

$p_o=0.7$ is the value that we want to test

$\alpha=0.01$ represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is at least 0.45.:

Null hypothesis: $p\geq 0.45$

Alternative hypothesis: $p < 0.45$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.39 -0.45}{\sqrt{\frac{0.45(1-0.45)}{700}}}=-3.19$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a lef tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.01$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of interst is significantly lower than 0.45 and the claim is not appropiate

3 0

4 years ago

Calculate the unpaid balance, finance charge, and new balance using the unpaid balance method. Note: interest rate is given as a

quester [9]

Previous balance = $291.96

Payments/credits = $45.00

Unpaid balance = $ 291.96 - $45.00 = $ 246.96

Monthly Interest rate = 1.5 %

Finance charge = 1.5 % of $ 246.96= $3.70

Total balance to be paid when Finance charge is included = $ 246.96 + $3.70= $ 250.66

New purchases = $103.98

New balance = $ 250.66 + $103.98 = $ 354.64

8 0

3 years ago

Can the sum of two irrational numbers ever be a rational number?

andrew-mc [135]

Irrational numbers are numbers that can not be written as a ratio of two integers. (example: square root of 2). Rational numbers on the other hand can be written as a ratio, as decimal or percentage.
If X is a irrational number, than the number Y=1-X is also irrational and the sum of these two irrational numbers is: X+Y=X+1-X=1 is rational number.
So, the sum of two irrational numbers can be a rational number.

7 0

4 years ago

50 points!

Nana76 [90]

Answer:

y = 5 − 2x

4x + 2y = 10

(Infinite solutions)

x = 26 − 3y

2x + 6y = 22

(No solution)

5x + 4y = 6