Write using algebra.
1 answer:
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By applying the knowledge of similar triangles, the lengths of AE and AB are:
a.
b.
<em>See the image in the attachment for the referred diagram.</em>
<em />
- The two triangles, triangle AEC and triangle BDC are similar triangles.
- Therefore, the ratio of the corresponding sides of triangles AEC and BDC will be the same.
<em>This implies that</em>:
- AC/BC = EC/DC = AE/DB
<em><u>Given:</u></em>
<u>a. </u><u>Find the length of </u><u>AE</u><u>:</u>
EC/DC = AE/DB
- Plug in the values
- Cross multiply
- Divide both sides by 5.4
<u>b. </u><u>Find the length of </u><u>AB:</u>
AC = 6.15 cm
To find BC, use AC/BC = EC/DC.
- Plug in the values
- Cross multiply
- Thus:
- Substitute
Therefore, by applying the knowledge of similar triangles, the lengths of AE and AB are:
a.
b.
Learn more here:
<h3>Answer: 24/25</h3>
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Explanation:
Sine is given to be negative, and so is tangent. This only happens in quadrant Q4
Recall that y = sin(theta), so if sin(theta) < 0, then we're below the x axis.
If tan(theta) < 0, then this means cos(theta) > 0
So we have y < 0 and x > 0 which places the angle somewhere in Q4.
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Draw a right triangle as shown below in the attached image. We have AC = 25 and BC = 7. Use the pythagorean theorem to find that AB = 24
So this is what your steps may look like
a^2+b^2 = c^2
7^2+b^2 = 25^2
b^2+49 = 625
b^2 = 625-49
b^2 = 576
b = sqrt(576)
b = 24
So because AB = 24, we know that the cosine of the angle is adjacent/hypotenuse = 24/25
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As an alternative, you could use the trig identity
sin^2(x) + cos^2(x) = 1
and plug in the given value of sine to solve for cosine. The cosine value result will be positive since we're in Q4.
So,
sin^2(x) + cos^2(x) = 1
(-7/25)^2 + cos^2(x) = 1
(49/625) + cos^2(x) = 1
cos^2(x) = 1 - (49/625)
cos^2(x) = (625/625) - (49/625)
cos^2(x) = (625-49)/625
cos^2(x) = 576/625
cos(x) = sqrt(576/625)
cos(x) = sqrt(576)/sqrt(625)
cos(x) = 24/25
This is effectively a rephrasing of the previous section since the pythagorean trig identity is more or less the pythagorean theorem (just in a trig form)