Answer:
Denote AH as height of triangle ABC, with H lies on BC.
Applying sine theorem:
AH/AC = sin 60
=> AH = AC x sin 60 = 47 x sqrt(3)/2 = 40.7
=> Area of triangle ABC is calculated by:
A = AH x BC x (1/2) = 40.7 x 30 x (1/2) = 610.5 = ~611
=> Option C is correct.
Hope this helps!
:)
Answer:

<h3><u>m=18</u> is the right answer.</h3>
Say this: "after x=2, g(x) exceeds f(x). Note that for x=3, g(3) > f(3). Check that out.
Answer:
Distance =(x2−x1)2+(y2−y1)2−−−−−−−−−−−−−−−−−−√
Step-by-step explanation:
The answer is provided above.
Distance =(x2−x1)2+(y2−y1)2−−−−−−−−−−−−−−−−−−√
Hope this helps.
The equations standered form is y=-x^2/8-x/2-9/2