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kow [346]
3 years ago
5

Pleaseeeeee (correct answer pls)

Mathematics
2 answers:
Marina86 [1]3 years ago
4 0

Answer:

3.8^12

Step-by-step explanation:

3x4 is 12

SSSSS [86.1K]3 years ago
4 0

Answer:

3.8 x 3.8 x 3.8=54.872

so therefore it is 54.872 to the power of 4

Step-by-step explanation:

You might be interested in
Find the measures of all four angles if 3·(m∠1+m∠3) = m∠2+m∠4.
mixas84 [53]

Answer:

Step-by-step explanation:

m∠1=m∠3

m∠2=m∠4

3*(m∠1+m∠3)=m∠2+m∠4

3*(m∠1+m∠1)=m∠2+m∠2

3×2 m∠1=2 m∠2

m∠2=3 m∠1

now m∠1+m∠2=180°

m∠1+3 m ∠1=180

4 m∠1=180

m∠1=180/4=45°

m∠3=45°

m∠2=180-m∠1=180-45=135°

m∠4=135°

5 0
3 years ago
Help me Please....................
MakcuM [25]

9514 1404 393

Answer:

  1.3363

Step-by-step explanation:

The basic idea here is to find an expression for the direction vector between a point on L1 and a point on L2. Then, solve for the points on L1 and L2 that make that vector perpendicular to both lines L1 and L2. (The dot product of direction vectors is zero.) The distance between the points found is the shortest distance between the lines.

__

Let P be a point on L1. Then the parametric equation for P is ...

  P = (6t, 0, -t) . . . . . . origin + t × direction vector

Let Q be a point on L2. The direction vector for L2 is given by the difference between the given points. It is (4-1, 1-(-1), 6-1) = (3, 2, 5). Then the parametric equation for Q is ...

  Q = (3s+1, 2s-1, 5s+1) . . . . (1, -1, 1) + s × direction vector

The direction vector for PQ is ...

  Q -P = (3s+1-6t, 2s-1, 5s+1+t)

The dot product of this and the two lines' direction vectors will be zero:

  (3s+1-6t, 2s-1, 5s+1+t)·(6, 0, -1) = 0 = 13s -37t +5 . . . perpendicular to L1

  (3s+1-6t, 2s-1, 5s+1+t)·(3, 2, 5) = 0 = 38s -13t +6 . . . perpendicular to L2

The solution to these equations is ...

  s = -157/1237

  t = 112/1237

Then (Q-P) becomes (94, -1551, 564)/1237, and its length is ...

  |PQ| = √(94² +1551² +564²)/1237 ≈ 1.3363

The distance between the two lines is about 1.3363 units.

8 0
3 years ago
First grade math its blank minus 1 =10-3<br><br>-1=10-3
marissa [1.9K]
___-1=10-3
x-1=10-3
x-1=7
x=8
therefore the blank is 8
7 0
2 years ago
Read 2 more answers
Solve and check the following equation. 8d + 21 = 12d + 5 <br><br><br><br> d =
olganol [36]

Subtract 8d from both sides

21 = 12d + 5 - 8d

Simplify 12d + 5 - 8d to 4d + 5

21 = 4d + 5

Subtract 5 from both sides

21 - 5 = 4d

Simplify 21 - 5 to 16

16 = 4d

Divide both side by 4

16/4 = d

Simplify 16/4 to 4

4 = d

Switch sides

d = 4

<u>Check answer</u>

8d + 21 =12d + 5

Let d = 4

8 × 4 + 21 = 12 × 4 + 5

Simplify 8 × 4 to 32

32 + 21 = 12 × 4 + 5

Simplify 12 × 4 to 48

32 + 21 = 48 + 5

Simplify 32 + 21 to 53

53 = 48 + 5

Simplify 48 + 5 to 53

53 = 53

3 0
3 years ago
The two triangle below are Similar:<br><br> Find the distance y.
MrMuchimi

Answer:

so...y=2

................

6 0
3 years ago
Read 2 more answers
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