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3 years ago

Find the interquartile range (IQR) of the data in the dot plot below. 0,0,0,1,2,2,2,2,2,3,4

Mathematics

2 answers:

lesantik [10]3 years ago

8 0

Answer:

=0.333

Step-by-step explanation:

THE MEDIAN=2

Median is always Q2 half range

IQR=Q1-Q3

Q1 is 1/4*2÷1/2=1

Q3 is 1/4×2÷3/4=1.333

1.333-1=0.333

kifflom [539]3 years ago

5 0

Answer:

Step-by-step explanation:

Q2 = 2

Q1 = 0

Q3 = 2

IQR = 2 - 0 = 2

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Answer:

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Step-by-step explanation:

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2 years ago

A distance AB is observed repeatedly using the same equipment and procedures, and the results, in meters, are listed below: 67.4

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Answer:

a) $\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

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$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

Step-by-step explanation:

For this case we have the following dataset:

67.401, 67.400, 67.402, 67.396, 67.406, 67.401, 67.396, 67.401, 67.405, and 67.404

Part a: Determine the most probable value.

For this case the most probably value would be the sample mean given by this formula:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

And if we replace we got:

$\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

Part b: Determine the standard deviation

The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

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<h3>Answer:</h3>

f(x) = -(x -2)² +3

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We can fill in the vertex (h, k) values immediately in the vertex form ...

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... -4 = 4a . . . . . . . . . subtract 3, simplify

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