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Triss [41]
3 years ago
12

Find the interquartile range (IQR) of the data in the dot plot below. 0,0,0,1,2,2,2,2,2,3,4

Mathematics
2 answers:
lesantik [10]3 years ago
8 0

Answer:

=0.333

Step-by-step explanation:

THE MEDIAN=2

Median is always Q2 half range

IQR=Q1-Q3

Q1 is 1/4*2÷1/2=1

Q3 is 1/4×2÷3/4=1.333

1.333-1=0.333

kifflom [539]3 years ago
5 0

Answer:

2

Step-by-step explanation:

Q2 = 2

Q1 = 0

Q3 = 2

IQR = 2 - 0 = 2

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A marching band is arranged in rows of 7 the first row has 3 band members and each row after the first has 2 more band members t
pav-90 [236]

Answer:

a_{n}= 1+2n and 63

Step-by-step explanation:

the question belongs to arithmetic sequence and a_{n} can be determined by the formula

a_{n}= a1 + d (n-1)

Let " a_{n} " represents the number of band members in the nth row

and 'd' represents the common difference.( as stated each row  has 2 more band members than the row before it)

therefore, d=2

'a1' represents first row that has three members. So, a1 = 3

->Rule for nth term will be:

a_{n}= 3 + 2(n-1)

a_{n}= 3 + 2n -2

a_{n}= 1+2n

-> In order to find total number of band members 'S_{7}'

Let S_{n} represent total number in n rows

We'll use the formula, i.e  S_{n} = n/1 (a_{1} +  a_{n})

where, n is the number of terms, a_{1} is the first term and a_{n} is the last term

So,

n=7

a_{7} = 1 + 2(7)= 15

=>S_{7} = 7/2 (3 + 15)

S_{7} = 63

The total number of band members are 63

8 0
3 years ago
To the nearest hundredth, how many cm are in 36 in? (1 in = 2.54 cm)
PIT_PIT [208]
<span>C) 91.44 cm

hope this helps :) </span>
7 0
3 years ago
Read 2 more answers
HELP ON A TEST
sergejj [24]

Answer:

(-1, 6)

Step-by-step explanation:

The midpoint of a line segment is effectively the point that lies halfway between two pairs of coordinates on a line. The coordinates we're concerned with here are (-4, 10) and (2, 2). So first think about what is halfway between -4 and 2 (or you can add -4 and 2 then divide by 2) and do the same with 10 and 2. This will give you (-1, 6).

5 0
3 years ago
Find the tangent line equation of the curve at the given point. Y=arcsin(7x) at the point where x=sqrt2/14
Mumz [18]

Answer:

Y-\frac{\pi}{2} =\frac{\pi}{2} (x+\sqrt{\frac{1}{7}})

Step-by-step explanation:

The equation of the curve is

Y = sin^{-1}(7x)

To find the equation of tangent we need to differentiate this equation w.r.t x

So, differentiating we get

Y'=\frac{7}{\sqrt{1-49x^2} }

This would give the slope of the tangent line at any given point of which x coordinate is known. In the present case it is  x = \sqrt{\frac{1}{7} }

Then slope would accordingly be

Y'=\frac{7}{\sqrt{1-49/49} }

= ∞

For, x = \sqrt{\frac{1}{7} }, Y = sin^{-1}(7/7)= \pi/2

Equation of tangent line, in the point slope form, would be Y-\frac{\pi}{2} =\frac{\pi}{2} (x+\sqrt{\frac{1}{7}})

4 0
3 years ago
Write the equation of the line through the indicated point with the indicated slope. write the final answer in the form y equals
Assoli18 [71]

y = - 4x + 13


slope = -4

y-intercept = 13

8 0
3 years ago
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