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makkiz [27]
4 years ago
14

The function h(x) = x squared+3 and g(x) = x squared-6. if g(x)=h(x)+k what is the value of k

Mathematics
1 answer:
kotykmax [81]4 years ago
4 0

Answer:

k=-9

Step-by-step explanation:

The given functions are

h(x) =  {x}^{2}  + 3

and

g(x) =  {x}^{2}  - 6

We want to find the value of k, for which

g(x) = h(x) + k

This means we need to extract g(x) from f(x) to get:

g(x) =  {x}^{2}  + 3 - 9

Or

g(x) = ( {x}^{2}  + 3)  + (- 9)

g(x) =h(x)+  - 9

Therefore k=-9

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Answer:

h(x) * s(x) = 200(1.05)^(x - 1)

Step-by-step explanation:

Our interest equation is s(x) = (1.05)^(x - 1). This is actually a part of a bigger formula for calculating the amount of money accumulated including interest:

A = P(1 + r)^n, where A is the total, P is the principal amount (initial amount), r is the interest rate, and n is the time

Here, we technically already have the (1 + r)^n part; it's just (1.05)^(x - 1). The principle, though, will actually be the 200 because she starts out at $200.

Thus, to combine these, we simply multiply them together to get:

h(x) * s(x) = 200(1.05)^(x - 1)

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4 years ago
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Which formula represents Charles's law? ?
victus00 [196]

Answer:

The answer would be: V1/T1=V2/T2

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3 years ago
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Some doctors recommend that no more than 30% of a person's daily calories come from fats. Following this recommendation, if you
White raven [17]

2400 divided by 10 is 240 and 240 x 3 = 720 so your answer would be 720 calories per day

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3 years ago
Help with both questions offering 10 points
Alexandra [31]

Answer:

\:\mathrm{First\: problem:\:}-2,\\\:\mathrm{Second\: problem:\: }-3

Step-by-step explanation:

The slope of a line passing through points (x_1, y_1) and (x_2, y_2) is:

m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}

Plugging in any two points in the table we have:

<u>First problem:</u>

<u />m=\frac{1-5}{2-0}=\frac{-4}{2}=\fbox{$-2$}<u />

<u>Second problem:</u>

<u />m=\frac{-1-5}{2-0}=\frac{-6}{2}=\fbox{$-3$}<u />

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If an object is propelled upward from a height of s feet at an initial velocity of v feet per​ second, then its height h after t
Sergio039 [100]

From the given information we can write the equation:

-16t^2 +96t + 4 = 112

-16t^2 + 96t + 4 - 112 = 0

-16t^2 + 96t - 108 = 0

simplify, change the signs, divide by -4

4t^2 - 24t + 27 = 0


You can use the qudratic formula but this will factor to

(2t-3)(2t-9) = 0

Two solutions

t = 3/2

t = 1.5 seconds at 112 ft on the way up

and

t = 9/2

t = 4.5 seconds at 112 ft on the way back down

Graphically, (green line is 112 ft)


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