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makkiz [27]
4 years ago
14

The function h(x) = x squared+3 and g(x) = x squared-6. if g(x)=h(x)+k what is the value of k

Mathematics
1 answer:
kotykmax [81]4 years ago
4 0

Answer:

k=-9

Step-by-step explanation:

The given functions are

h(x) =  {x}^{2}  + 3

and

g(x) =  {x}^{2}  - 6

We want to find the value of k, for which

g(x) = h(x) + k

This means we need to extract g(x) from f(x) to get:

g(x) =  {x}^{2}  + 3 - 9

Or

g(x) = ( {x}^{2}  + 3)  + (- 9)

g(x) =h(x)+  - 9

Therefore k=-9

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Answer:

Option (4) is correct about BQ

Step-by-step explanation:

Given : From the figure : ∠BQA = 54° and ∠BAQ = 36°

Now, Since ∠BAQ = 36° > 30°  

So, ∠BAQ is not acute.

⇒ (1) is rejected.

Also, ∠BQA = 54° > 30°  

So, ∠BQA is not acute.

⇒ (2) is rejected.

Now, in ΔABQ, By using angle sum property of a triangle

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