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KIM [24]
3 years ago
13

Why has the atomic theory changed so much over the last several centuries?

Chemistry
1 answer:
nata0808 [166]3 years ago
4 0
The technology and exiting knowledge we have of the atom has gotten better over the years allowing for greater accuracy
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ΑC2H6O+βO2 → γC2H4O2+δH2O
olga2289 [7]
Balancing the equation, we get:

2C₂H₆O + O₂ → 2C₂H₄O₂ + 2H₂O

So 
α = 2
β = 1
γ = 2
δ = 2
4 0
3 years ago
Is one quarter the size of earth, has no moons, and has an almost non-existent atmosphere
PIT_PIT [208]

For the answer to the question above,
If you mean planet, that would be Mercury. There are other objects in our solar system that could fit the criteria. 
Our moon, Ganymede, and Callisto are about a quarter the size of Earth and have no atmosphere or moon.
7 0
3 years ago
Read 2 more answers
The 1h nmr spectra corresponds to an alcohol with the molecular formula c5h12o. Deduce the structure from the spectra.
Sav [38]

Answer:

The question is incomplete. The spectra can be seen in the first picture in the attachment.

The molecule corresponds to the  <em>tert</em>-amyl alcohol.

Explanation:

From the molecular formula, we can calculate the double bond equivalent, to know if there is any <u>unsaturation in the molecule</u>. For a compound of molecular formula CxHyOzXqNp

DBE= (2x+2)- (y+q-p) ÷ 2

DBE= (2.2+2)-12 ÷12 = 0

Therefore, <u>the molecule does not have any unsaturation</u>.

Considering the chemical shift values and the multiplicity, the structure that satisfies the spectra corresponds to the <em>tert</em>-amyl alcohol (structure in attachment).

7 0
3 years ago
What mass of na2co3 is present in 0.650 l of a 0.505 m na2co3 solution?
Vladimir79 [104]
V=0.650 L
c=0.505 mol/L
M(Na₂CO₃)=106.0 g/mol

the amount of substance of sodium carbonate is:
n(Na₂CO₃)=vc

the mass of sodium carbonate is:
m(Na₂CO₃)=n(Na₂CO₃)M(Na₂CO₃)

m(Na₂CO₃)=vcM(Na₂CO₃)

m(Na₂CO₃)=0.650*0.505*106.0=34.7945 g



3 0
3 years ago
Cl2 + 2OH− → Cl− + ClO− + H2O
Nataly_w [17]
Cl2(g) -------> Cl-(aq) + ClO-(aq) 

2e- + Cl2(g) -------> 2Cl-(aq) [reduction] 

4OH-(aq) + Cl2(g) -----------> 2ClO-(aq) + 2H2O(l) + 2e- [oxidation] 
______________________________________... 
2OH-(aq) + Cl2(g) --------> Cl-(aq) + ClO-(aq) + H2O(l)
4 0
3 years ago
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