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stiks02 [169]
2 years ago
13

250 ml mercury to lbs

Chemistry
1 answer:
VashaNatasha [74]2 years ago
3 0

Answer:

Amount : 250 milliliters (ml) of mercury

Equals: 7.46 pounds (lb) in mercury

Explanation:

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On the 14 point pH scale, soaps and cleaning solutions are typically -
Ronch [10]

Answer:The answer is 8-14

Explanation:It can range from 9-10 or

or above to 14 depending on the amount of leached wood ash(lye) a.k.a potassium carbonate which is an alkalline compound

6 0
3 years ago
Read 2 more answers
Calculate the pressure (in kpa) of 1.5 mole of helium gas at 354 k when it occupies a volume of 16.5l.
3241004551 [841]

Answer:

267.57 kPa

Explanation:

Ideal gas law:

PV = n RT        R = 8.314462    L-kPa/K-mol

P (16.5) = 1.5 (8.314462)(354)       P = 267.57 kPa

8 0
2 years ago
The mass of an empty crucible was 17.556g. The mass of the crucible and a hydrate was 21.018 g. The mass of the crucible and anh
Charra [1.4K]

Answer:

A. 1.377 g

B. 16.5%

Explanation:

To find the water loss, subtract the salt and crucible mass from the hydrate and crucible mass

21.018 - 19.641 = 1.377

To find the water mass percentage, divide the empty crucible mass by the mass of the hydrate and crucible. Then, subtract that number from 1.

17.556 ÷ 21.018 = 0.835284

1 - 0.835284 = 0.164716

If you want to add an extra step, multiply this number by 100 to get the percentage.

0.164716 x 100 = 16.4716

5 0
3 years ago
A gas at STP occupies 16 L of space. If the pressure changes to 2.6 atm and the temperature increases to 195 degrees C, what is
Tju [1.3M]

The new volume of a gas at STP that occupies 16L of space is 27.43L.

<h3>HOW TO CALCULATE VOLUME?</h3>

The volume of a given gas can be calculated using the following expression:

P1V1/T1 = P2V2/T2

Where;

  • P1 = initial pressure
  • P2 = final pressure
  • V1 = initial volume
  • V2 = final volume
  • T1 = initial temperature
  • T2 = final temperature

1 × 16/273 = 2.6 × V2/468

16/273 = 2.6V2/468

0.0586 × 468 = 2.6V2

V2 = 27.43

Therefore, the new volume of a gas at STP that occupies 16L of space is 27.43L.

Learn more about volume at: brainly.com/question/1578538

5 0
3 years ago
What is e cell (in units of volts) for a galvanic cell constructed from barium and manganese electrodes?
gulaghasi [49]

Main Answer: The standard electrode potential of galvanic cell constructed from barium and manganese electrode is 4.097.

Explanation:

When the galvanic cell constructed between Manganese and Barium, the half reactions will be as follows:

Mn2+(aq) + 2e-⟶ Mn(s)                                             E1 = −1.185

Ba2+(aq) + 2e-⟶ Ba(s)                                                 E2 = −2.912

By considering the above two reactions, the standard electrode potential can be calculated.

The galvanic cell standard electrode potential is given by E1 + E2 = 1.185 + 2.912 = 4.097 volts

What is standard electrode potential?

Standard electrode potential is defined as the measure of reducing power of any compound or element. Its units are volts.

To know more about galvanic cell, please visit:

brainly.com/question/13031093

#SPJ4

3 0
2 years ago
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