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geniusboy [140]
3 years ago
13

Write an equivalent expression for 7a + 21

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
4 0
7(a+3) this is the answer im pretty sure
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What are the steps to find the lower and upper quartiles in a data set
Minchanka [31]

Answer:

The steps to finding the upper and lower quartiles are given in the first choice.

1.  Order the data from least to greatest. If you don't do this, the data is random.

2.  Find the median - you will do this so that you can find the midpoint of the data set (half of of the data is smaller and half of the data is larger).

3.  Find the lower quartile - this is the half of the lower half of numbers; think of it as breaking the lower half of the data into 2 sections.  

4.  Find the upper quartile - this is the half of the greater half of numbers; this will break the upper half of the data into 2 sections.  

 

8 0
3 years ago
What’s the sum(2r-6)+4(r-3
vlabodo [156]

Answer:

=6r−18

Step-by-step explanation:

Distribute:

=2r+−6+(4)(r)+(4)(−3)

=2r+−6+4r+−12

Combine Like Terms:

=2r+−6+4r+−12

=(2r+4r)+(−6+−12)

=6r+−18

4 0
3 years ago
Read 2 more answers
How to convert 10.6 into a fraction
Sati [7]
10 3/5 is the correct answer
7 0
3 years ago
Read 2 more answers
A type of rope weighs 4 ounces per inch.
yuradex [85]

Answer:

Answer:3 pounds per foot

4 0
3 years ago
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Help answering this simple Series Question? I don't know what I did wrong!
Tatiana [17]
Looks like you just evaluated the summand for the given value of n, whereas the question is asking you to find the value of the sum for the first n terms.

Let S_k=\displaystyle\sum_{n=1}^k\frac3{(-2)^n}. Then S_k is the kth partial sum.

S_1 happens to be the first term in the series, which is why that box is marked correct:

S_1=\displaystyle\sum_{n=1}^1\frac3{(-2)^n}=\frac3{(-2)^1}=-1.5

But the next partial sum is not correct:

S_2=\displaystyle\sum_{n=1}^2\frac3{(-2)^n}=\frac3{(-2)^1}+\frac3{(-2)^2}=-0.75

and this is not the same notion as the second term (which indeed is 0.75) in the series.
5 0
3 years ago
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