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stepladder [879]
3 years ago
14

Rachel is setting up tables for a party. Four of the tables are covered with red tablecloths, and eight of the tables are covere

d with white tablecloths. Guests will be randomly seated at the tables when they arrive. Each table can seat 8 guests. What is the probability that the first guest to arrive will be seated at a table with a red tablecloth?
Mathematics
1 answer:
Gnom [1K]3 years ago
7 0

Answer:

it is a 1/3 chance

Step-by-step explanation:

there are 12 tables in total, 4 red and 8 blue. you can render that down to 1 red and 2 blue, now there are 3 tables and only 1 is red, therefore the answer is 1/3 chance

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x - 4 = √3y

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Answer:

<h2><em>(</em><em>4</em><em>,</em><em>5</em><em>)</em></h2>

<em>sol</em><em>ution</em><em>,</em>

<em>A</em><em>(</em><em>2</em><em>,</em><em>7</em><em>)</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>></em><em> </em><em>(</em><em>X1,</em><em>y1</em><em>)</em>

<em>B</em><em>(</em><em>6</em><em>,</em><em>3</em><em>)</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>></em><em>(</em><em>x2</em><em>,</em><em>y2</em><em>)</em>

<em>now</em><em>,</em>

<em>ab = ( \frac{x1 + x1}{2}  \: , \frac{y1 + y2}{2} ) \\  =  (\frac{2 + 6}{2}  \: , \frac{7 + 3}{2} ) \\  = ( \frac{8}{2}  \:,  \frac{10}{2} ) \\  = (4 ,\: 5)</em>

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