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gulaghasi [49]
2 years ago
14

Help find the measure of the arc!!!

Mathematics
1 answer:
Art [367]2 years ago
8 0
270..............................................
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Solve for x.
Ivanshal [37]

Answer:

x = -3.25

Step-by-step explanation:

2/5 = 0.4

0.4x - 0.2 = -2(3/4)

-2(3/4) = -2/1 * 3/4 = -6/4

0.4x - 0.2 = -6/4

Convert to fraction

2/5x - 1/5 = -6/4

Add 1/5 to both sides

-6/4 + 1/5 = -30/20 + 4/20 = -26/20

2/5x = -26/20

Convert to decimal

0.4x = -1.3

-1.3/0.4 = -3.25

x = -3.25

8 0
2 years ago
How tall is the flag pole (please give explanation too)
Tpy6a [65]

Answer:

  22 3/4 ft

Step-by-step explanation:

The diagram seems to show a 6 1/2 ft person casting a 9 ft shadow at the same time a flagpole is casting a 31 1/2 ft shadow. You want the height of the flagpole.

<h3>Proportion</h3>

Shadow lengths are presumed proportional to the height of the object making them. This means ...

  h/(31 1/2) = (6 1/2)/9 . . . . . all lengths in feet

Multiplying by 31 1/2, we get ...

  h = (31 1/2)(6 1/2)/9 = (819/4)/9 = 91/4

  h = 22 3/4 . . . . ft

The flagpole is 22 3/4 feet tall.

3 0
1 year ago
Consider the function f(x) = -4x²-9x+20.<br><br> Determine f(-2)=
hoa [83]

Step-by-step explanation:

  • you just substitute (-2) into the x values of the above function
  1. f( - 2) =  - 4( - 2)^{2}  - 9( - 2) + 20 \\ f( - 2) = 22
3 0
2 years ago
A football is punted and follows a path from the line of scrimmage similar to the quadratic equation: y= -¹⁄₂₀ (x-25)² + 30 wher
cluponka [151]
Do it on a Calculator just type it in
8 0
2 years ago
4 cot theta<br>=<br>tan theta<br>how do I I find the value of quadrant?​
Ray Of Light [21]

Answer:

4cotα=tanα

4(1/tanα)=tanα

(4/tanα)=tanα

cross multiply

=> 4=tan²α

√4=√tan²α

±2=tanα

α=arc( tan) |2|

α=63.4° ( in first quadrant)

and

α=180+63.4=243.4 in the third quadrant

since we also found a negative answer( i.e –2) then α also lies in quadrants where it gives a negative value(i.e second and fourth quadrants)

α=180–63.4=116.6° in the second quadrant

α=360–63.4=296.6 in the fourth quadrant

therefore theta( in my case, alpha) lies in all four quadrants and is equal to:

α=63.4°,243.4°,116.6°and 296.6°

5 0
3 years ago
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