<span>(y=mx+b) or (ax+by=c) hope this helped
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Answer:
y=2/5x-15
Step-by-step explanation:
y-y=m(x-x¹)
y-(-11)=2/5(x-10)
y+11=2/5x-4
-11 -11
y=2/5x-15
Let the smaller one is x so the larger is x+1
x(x+1)=1332
x^2+x=1332
x^2 +x -1332 =0
(x - 36)(x + 37) =0
so x = 36 or x = -37
therefor the larger integer is either 37 or -36
Since 5 winning numbers are draw and there are exactly 2 winning numbers, the other 3 numbers chosen have to be incorrect.
The 2 numbers picked right, there are 5C2=10 different possibilities.
The other 3 numbers are just picked from the rest of the 32 numbers. Getting there are 32C3=4960 different possibilities.
For each set of 2 correct winning numbers, you could have the 4960 different losing numbers to match up to make a unique set. This meant that there are 4690*10=46900 different total possibilities.
Now the total different outcomes of how you can choose the numbers are 37C5=435897 outcomes.
Now the way to find probabilities is want/total
The want is 46900 and the total is 435897
Doing the division you get the number rounded to the nearest thousandths as 0.107 or in percent form as
10.759% chance of picking exactly 2 winning numbers.
This seems like a competition problem of some sort therefore I assume that you already know what combinations in form nCk and permutation in form nPk means.
