Which expressions are equivalent to 5^18?

Mathematics

1 answer:

s2008m [1.1K]3 years ago

7 0

Answer:

D.5^12 X 5^6 is the correct answer.

Step-by-step explanation:

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Find the center-radius form of the equation of the circle described.

Kitty [74]

Answer:

Correct answer: (x-√2)² + (y-√5)² = 3

Step-by-step explanation:

Given data: Center (x,y) = (√2,√5) and r = √3

The canonical or cartesian form of the equation of the circle is:

( x-p )² + ( y-q )² = r²

Where p is the x coordinate of the center, q is the y coordinate of the center and r is the radius of the circle.

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3 years ago

Simplify the following expressions.

baherus [9]

1. 36x + 4
2. 30n + 42
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4. 24p -28
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2 years ago

5.3.4 Journal: Two-Variable Systems Elimination <br><br> I need urgent help

max2010maxim [7]

Answer:

1) X stands for individual acts and y, group acts. 2) Each scenario describes a different period in minutes, but each one respecting their different amounts (individual and group acts). 3) $S=\left \{ 5,10 \right \}$

Step-by-step explanation:

Completing with what was found:

<em> 1) Here is a summary of the scenario your classmate presented for the talent show:Main show The main show will last two hours and will include twelve individual acts and six group acts.Final show The final show will last 30 minutes and will include the top four individual acts and the top group act.The equations he came up with are: 12x+ 6y= 120, 4x+ y= 30</em>

1. What do x and y represent in this situation?

X stands for individual acts and y, group acts.

Besides that, In the system of equation, they represent the time for x, and the time for y.

2. Do you agree that your classmate set up the equations correctly? Explain why or why not.

Yes, that's right. Each scenario describes a different period in minutes, but each one respecting their different amounts (individual and group acts). Either for 120 minutes or 30 minutes length. And their sum totalizing the whole period.

3. Solving the system by Elimination

$\left\{\begin{matrix}12x+ 6y= 120\\ 4x+ y= 30\end{matrix}\right.\\\left\{\begin{matrix}12x+ 6y= 120\\ 4x+ y= 30\:*(-3)\end{matrix}\right.\\\left\{\begin{matrix}12x+ 6y= 120\\ -12x+ -3y= -90\end{matrix}\right.\\3y=30\Rightarrow y=10\\4x+(10)=30\Rightarrow 4x=20\Rightarrow x=5\\S=\left \{ 5,10 \right \}$