What is the equation for the line perpendicular to the line represented by the equation y = 13x – 2 that passes through the poin

Question

1 year ago

7

t (4, –7)?

1 answer:

laiz [17] · Answer 1 · 2023-08-08T21:40:00+03:00

The equation of the perpendicular line is:

y = (-1/13)*x - 87/13

<h3>How to get the line equation?</h3>

For a general linear equation:

y = a*x + b

Another linear equation that is perpendicular to the above one is given by:

y = (-1/a)*x + c

Where a, b, and c are real numbers.

In this case, we want to find a perpendicular line to:

y = 13*x - 2

Then it will be something like:

y = (-1/13)*x + c

To find the value of c, we use the fact that it must pass through the point (4, -7), then:

-7 = (-1/13)*4 + c

Now we can solve that for c:

-7 + 4/13 = c

-87/13

Then the linear equation is:

y = (-1/13)*x - 87/13

If you want to learn more about linear equations:

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