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3 years ago

Helllppppppppppppppppppppppppppppp

Mathematics

1 answer:

Georgia [21]3 years ago

4 0

The equation: n - 4 = -15

Now let's solve our equation for n.

n - 4 = -15

Add 4 to both sides.

n = -11

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When graphed in the (x,y) coordinate plane, at what point do the lines x - y = 12

Alex17521 [72]

Answer:

(14, 2).

Step-by-step explanation:

x - y = 12

y = 2

Solving this system:

Plug y = 2 into the first equation:

x - 2 = 12

x = 14.

Therefore the point of intersection is at (14, 2).

4 0

3 years ago

Write a slope-intercept equation for a line passing through the point (5,-5) that is parallel to the line x = -2. Then write a s

Gnesinka [82]

Answer:

1. y=-2x+5

2. y=1/2x-7.5

Step-by-step explanation:

you plug in the cordinates for the y intercept and you already have the slope.

y=mx+b

m= slope which is -2

6 0

3 years ago

Can someone please solve and explain these questions??? With work please.

ankoles [38]

Y=1 because on each equation it needs 1 for it to be the answer

8 0

2 years ago

Work out <br><br> 5 3/4 - 2 1/4

Klio2033 [76]

Answer:

3 1/2

Step-by-step explanation:

So because the fraction in attatched to the whole numbers have the same denominator you can literally just subtract the whole numbers and the fractions. (You do them seperatly) (5-2)=3 (3/4-1/4) = 2/4 or 1/2

4 0

1 year ago

If y= 3x + 6, what is the minimum value of (x^3)(y)?

Rainbow [258]

Answer:

Given the statement: if y =3x+6.

Find the minimum value of $(x^3)(y)$

Let f(x) = $(x^3)(y)$

Substitute the value of y ;

$f(x)=(x^3)(3x+6)$

Distribute the terms;

$f(x)= 3x^4 + 6x^3$

The derivative value of f(x) with respect to x.

$\frac{df}{dx} =\frac{d}{dx}(3x^4+6x^3)$

Using $\frac{d}{dx}(x^n) = nx^{n-1}$

we have;

$\frac{df}{dx} =(12x^3+18x^2)$

Set $\frac{df}{dx} = 0$

then;

$(12x^3+18x^2) =0$

$6x^2(2x + 3) = 0$

By zero product property;

$6x^2=0$ and 2x + 3 = 0

⇒ x=0 and x = $-\frac{3}{2} = -1.5$

then;

at x = 0

f(0) = 0

and

x = -1.5

$f(-1.5) = 3(-1.5)^4 + 6(-1.5)^3 = 15.1875-20.25 = -5.0625$

Hence the minimum value of $(x^3)(y)$ is, -5.0625

3 0

3 years ago