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Pavel [41]
3 years ago
6

On an architect's blueprint, the front of a building measures 27 inches wide. The scale of the blueprint is 1 inch = 2 feet. How

wide will the front of the actual building be?
Mathematics
1 answer:
Lisa [10]3 years ago
7 0

Answer:

54

Step-by-step explanation:

Multiply 27 by 2

You get.........

54 :P

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Write the equation of the line parallel to the y axis at a distance of 7 units form it to is left​
Finger [1]

Answer:

x = -7

Step-by-step explanation:

Two parallel lines are lines that never intersect each other.

The y-axis can be written as x = 0.

Then if we want a parallel line to this one, it must be something like x = b

such that b ≠ 0.

Now we want that the distance between our line and the line x = 0 is 7 units to the left

(remember that the left is the negatie side of the axis)

then we can write:

b - 0 = -7

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katen-ka-za [31]

Answer:

Step-by-step explanation:

its a square, so 16*16 = 256

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const2013 [10]

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Step-by-step explanation:

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3 years ago
Solve 5(2x – 3) = x – 15 + 9x for x.
Alexxandr [17]

Answer:

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4 0
2 years ago
Mrs.Flores’ rectangular garden has a length of 20 meters and width of 15 meters. Her neighbor, Mr.Sosa, has a similar garden in
natima [27]

180 m

Step-by-step explanation:

Information given:

  • length of Mrs. Flores' garden= 20 m
  • width of Mrs. Flores' garden = 15 m
  • Scale factor = 3

Since scale factor is 3, to get measurements of sides Mr. Sosa's garden, sides of Mrs. Flores's have to be multiplied by 3. Hence,

  • length of Mr. Sosa's garden= 3×20= 60 m
  • width of Mr. Sosa's garden= 3×15= 45 m

 Diagonal of a rectangle = √length²+width²

Let Diagonal = D,

D= √60²+45²

=√3600+2025

=√5625

=75 m

If Mr. Sosa cut his garden diagonally,

perimeter= length+width+diagonal

=60+45+75=180 m

7 0
2 years ago
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