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tangare [24]
3 years ago
13

Please can someone help there 10 Points for it!!!!

Mathematics
1 answer:
torisob [31]3 years ago
8 0

Answer:

a) The missing terms are 9, 13, 21 and 25.

b) If we know that n_{1} = 9 and r = 4, then the n-th term of the sequence is represented by n_{n} = 9 +4\cdot (n-1).

Step-by-step explanation:

a) Given that elements of the sequence are found by increasing by the same amount, we infer that elements are part of an arithmetical progression. The rate of progression is now determined:

3\cdot r = 29-17

3\cdot r = 12

r = 4

The missing terms are:

n_{1} = 17 - 2\cdot (4)

n_{1} = 9

n_{2} = 17 - 4

n_{2} = 13

n_{4} = 17 +4

n_{4} = 21

n_{5} = 17 + 2\cdot (4)

n_{5} = 25

The missing terms are 9, 13, 21 and 25.

b) The formula for the arithmetical progression is represented by the following formula:

n_{n} = n_{1} + r\cdot (n-1) (1)

Where:

n_{1} - First element of the sequence.

n - Indicator associated with the element of the sequence.

r - Progression rate.

If we know that n_{1} = 9 and r = 4, then the n-th term of the sequence is represented by n_{n} = 9 +4\cdot (n-1).

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zhenek [66]

Answer:

<u>Alternative hypothesis 1</u>:  the mean amperage at which the fuses burn out is > 40 amperes.

<u>Alternative hypothesis 2</u>:  the mean amperage at which the fuses burn out is < 40 amperes.

Step-by-step explanation:

Recall that the null hypothesis is the fact you want to refute and is in doubt.

So, in this specific case, <em>the null hypothesis would be that the mean amperage at which the fuses burn out is 40 amperes. </em>

The alternative hypothesis are those that want to refute the null hypothesis, in this case there are 2:

<u>Alternative hypothesis 1:</u>  the mean amperage at which the fuses burn out is > 40 amperes.

<u>Alternative hypothesis 2:</u>  the mean amperage at which the fuses burn out is < 40 amperes.

6 0
3 years ago
8x^2+23=823<br><br> whats going to be the answer I got 0 am I right?
Naily [24]
1) No; you are incorrect.  "0" is NOT a solution.

Plug in "0" for "x" ;

8*0² + 23 =? 823? ; 

8*0  + 23 =? 823? ;

  0 + 23 = ? 823 ? ;  No! ;  "0 + 23 = 23 " ; NOT "823" .
_________________________________________________
2)  The answers:  x = 10, -10 ; or, write as:  x = ± 10 .
_________________________________________________

To solve:

GIven:  8x² + 23 = 823 ; 

Subtract "23" from EACH SIDE of the equation:
_____________________________________________
           8x² + 23 - 23 = 823 - 23 ; 
to get:  
           8x²  = 800 ; 

Now, divide EACH SIDE of the equation by "8" ; 

          8x² / 8 = 800 / 8 ;

to get:  x² = 100 ; 

        Take the "square root" of EACH SIDE of the equation; to isolate "x" on one side of the equation; and to solve for "x" ; 

          √(x²) = √(100) ;

             x  = <span>± 10 .

The answers:  x = 10, -10 ; or, write as:  x = </span><span>± 10 .
_____________________________________________________</span>
5 0
3 years ago
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