Answer:
θ = 0°
θ = 30°
θ = 150°
θ = 180°
Step-by-step explanation:
2sin² θ = sin θ
Then
2sin² θ - sin θ = 0
Then
sin θ (2sin θ - 1) = 0
Then
sin θ = 0 or 2sin θ - 1 = 0
Then
sin θ = 0 or sin θ = 1/2
…………………………………………
We have sin θ = 0 and - 270° ≤ θ ≤180°
Then
θ = 0 or θ = π = 180°
On the other hand,
sin θ = 1/2 and - 270° ≤ θ ≤180°
Then
θ = π÷6 or θ = 5π÷6
π÷6 = 30° and 5π÷6 = 150°
6&7. Also -7,-6 is the correct answer
It seems that the four graphs are the same and they do not have a negative change rate in the interval 0 to 2 in the x-axis.
A negative change rate means that when x increases the value of the function (y) decreases; this is, the function is decreasing in the interval being estudied, which is the same that going downward.
So, you must look for in your graphs where the equation is going downward.
For example, in the graph attached, that happens in any interval from negative infitity to 1.5.
The vertex will help you to identify it.
Given that the graph goes downward from negative infinity to the vertex, any interval that includes that range will have negative change.
You must look for a parabola that opens upward and whose vertex is in x = 2.
As the angles are complementary sin A = cos B and sin B = cos A
so sin A + sin B = 0.55 + 0.83 = 1.38
Yes, it is reasonable, because the ME is 7.1% and 48% falls within the range of 53.8% to 7.1%.
Calculating the ME:
![ME=\pm 2\sqrt{\frac{\hat{p}(1-\hat{p})}{N}}=\pm 2\sqrt{\frac{0.54(0.46)}{195}} =\pm 2\sqrt{\frac{0.2484}{195}}=0.071=7.1](https://tex.z-dn.net/?f=ME%3D%5Cpm%202%5Csqrt%7B%5Cfrac%7B%5Chat%7Bp%7D%281-%5Chat%7Bp%7D%29%7D%7BN%7D%7D%3D%5Cpm%202%5Csqrt%7B%5Cfrac%7B0.54%280.46%29%7D%7B195%7D%7D%0A%3D%5Cpm%202%5Csqrt%7B%5Cfrac%7B0.2484%7D%7B195%7D%7D%3D0.071%3D7.1)
The sample proportion was 53.8%. This gives us
53.8% +/- 7.1%