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3 years ago

4. Brandy is learning to make bracelets. She can make 4 bracelets in 10 minutes. What is her unit

Mathematics

1 answer:

vlabodo [156]3 years ago

3 0

Answer:

Step-by-step explanation:

4 is the rate because if she can make 4 in 10 min the the constant would be 4. By the way this didnt get answered becasue it was posted in spanish!

Have a great day!

Brainliest is appreciated!

- Lea

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What is the answer to 2(3x-4)-5=-7

kozerog [31]

Answer: x = 1

Step-by-step explanation:

1) Reorder the terms:

2(-4 + 3x) + -5 = -7

(-4 * 2 + 3x * 2) + -5 = -7

(-8 + 6x) + -5 = -7

2) Reorder the terms:

-8 + -5 + 6x = -7

3) Combine like terms: -8 + -5 = -13

-13 + 6x = -7

4) Solving

-13 + 6x = -7

5) Solving for variable 'x'.

6) Move all terms containing x to the left, all other terms to the right.

7) Add '13' to each side of the equation.

-13 + 13 + 6x = -7 + 13

8) Combine like terms: -13 + 13 = 0

0 + 6x = -7 + 13

6x = -7 + 13

9) Combine like terms: -7 + 13 = 6

6x = 6

10) Divide each side by '6'.

x = 1

11) Simplifying

x = 1

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3 years ago

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3 years ago

Over what interval would 50% of the entire population of engine speed values fall

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4 years ago

Which of the following is an equivalent number of calories per servings

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Step-by-step explanation:

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4 years ago

The quantity demanded x each month of Russo Espresso Makers is 250 when the unit price p is $138. The quantity demanded each mon

Stells [14]

Answer:

(a) $D(q)=\frac{-1}{25} q+148$

(b) $S(q)=\frac{1}{50}q+58$

Step-by-step explanation:

(a) For the demand equation D(q) we have

P1: 138 Q1: 250

P2: 108 Q2: 1000

We can find m, which is the slope of the demand equation,

$m=\frac{p_{2} -p_{1} }{q_{2} -q_{1} }=\frac{108-38}{1000-250} =\frac{-30}{750}=\frac{-1}{25}$

and then we find b, which is the point where the curve intersects the y axis.

We can do it by plugging one point and the slope into the line equation form:

$y=mx+b\\\\D(q)=mq+b\\\\138=\frac{-1}{25}(250) +b\\\\138=-10+b\\\\138+10=b=148$

With b: 148 and m: -1/25 we can write our demand equation D(q)

$D(q)=\frac{-1}{25} q+148$

(b) to find the supply equation S(q) we have

P1: 102 Q1: 2200

P2: 102 Q2: 700

Similarly we find m, and b

$m=\frac{p_{2} -p_{1} }{q_{2} -q_{1} }=\frac{72-102}{700-2200} =\frac{-30}{-1500}=\frac{1}{50}$

$y=mx+b\\\\D(q)=mq+b\\\\72=\frac{1}{50}(700) +b\\\\72=14+b\\\\72-14=b=58\\$

And we can write our Supply equation S(q):

$S(q)=\frac{1}{50}q+58$

(c) Now we may find the equilibrium quantity q* and the equilibrium price p* by writing D(q)=S(q), which means the demand equals the supply in equilibrium:

$D(q)=S(q)\\\\\frac{-1}{25}q+148=\frac{1}{50}q+58\\\\$

$148-58=\frac{1q}{50} +\frac{1q}{25} \\\\90= \frac{1q}{50} +\frac{2q}{50}\\\\90=\frac{3q}{50}\\ \\q=1500\\\\$

We plug 1500 as q into any equation, in this case S(q) and we get:

$S(q)=\frac{1}{50}q+58\\\\S(1500)=\frac{1}{50}(1500)+58\\\\S(1500)=30+58\\\\S(1500)=88$

Which is the equilibrium price p*.

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3 years ago