5k²-8k-45k+72 = 5k²-53k+72
Answer: 5k² - 53k + 72
Answer:
4
Step-by-step explanation:
10^2/5^2
Do the exponents first
10 to the 2nd power is 100
5 to the 2nd power is 25
100/25
100 divided by 25 is 4
So the answer is 4
Hope this helps!
Start with your lowest numbers, 3 bracelets have 24 beads. The easiest way to find your answer is to find out how many beads are on 1 bracelet. So 24/3 will give us that answer. 24/3=8. and then multiply 7 by 8 to get 56. then check your answer to make sure it fits.
3 x 8 = 24
5 x 8 = 40
7 x 8 = 56
9 x 8 = 72
The answer is: 10 x¹³ y¹⁰ .
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1x^8 * 2y^(10) * 5x^5 =
1* 2* 5 * x^8 * x^5 * y^(10) =
10 * x^(8+5) * y^(10) =
10 * x^(13) * y^(10) = 10 x^(13) y^10 ; write as:
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10 x¹³ y¹<span>⁰ .
<span>______________________________________________________</span></span>
Answer:
The answer is (d) ⇒ ![pq^{2}r\sqrt[3]{pr^{2}}](https://tex.z-dn.net/?f=pq%5E%7B2%7Dr%5Csqrt%5B3%5D%7Bpr%5E%7B2%7D%7D)
Step-by-step explanation:
* To simplify the cube roots:
If its number then the number must be written in the form x³
then we divide the power by 3 to cancel the radical
If its variable we divide its power by 3 to cancel the radical
∵ ![\sqrt[3]{p^{4}q^{6}r^{5}}=p^{\frac{4}{3}}q^{\frac{6}{3}}r^{\frac{5}{3}}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bp%5E%7B4%7Dq%5E%7B6%7Dr%5E%7B5%7D%7D%3Dp%5E%7B%5Cfrac%7B4%7D%7B3%7D%7Dq%5E%7B%5Cfrac%7B6%7D%7B3%7D%7Dr%5E%7B%5Cfrac%7B5%7D%7B3%7D%7D%7D)
∴ 
∵ ![p^{\frac{1}{3}}=\sqrt[3]{p}](https://tex.z-dn.net/?f=p%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7Bp%7D)
∵ ![r^{\frac{2}{3}}=\sqrt[3]{r^{2}}](https://tex.z-dn.net/?f=r%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7Br%5E%7B2%7D%7D)
∴ ![p(p)^{\frac{1}{3}}q^{2}r(r)^{\frac{2}{3}}=p(\sqrt[3]{p})q^{2}r(\sqrt[3]{r^{2}})](https://tex.z-dn.net/?f=p%28p%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7Dq%5E%7B2%7Dr%28r%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3Dp%28%5Csqrt%5B3%5D%7Bp%7D%29q%5E%7B2%7Dr%28%5Csqrt%5B3%5D%7Br%5E%7B2%7D%7D%29)
∴ ![prq^{2}\sqrt[3]{pr^{2}}}](https://tex.z-dn.net/?f=prq%5E%7B2%7D%5Csqrt%5B3%5D%7Bpr%5E%7B2%7D%7D%7D)
∴ The answer is (d)
