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3 years ago

Identify the value of x that makes each pair of ratios equivalent 6 to 8 and 18 to x

Mathematics

1 answer:

vaieri [72.5K]3 years ago

6 0

Set up a proportion
6/8 ≈ 18/x
cross multiply and solve for x, and get
x≈24

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If StartFraction pi Over 2 EndFraction less than t less than pi , which of the following is true?

oksian1 [2.3K]

Answer:

b. cosine t less than 0 and cotangent t greater than 0

Step-by-step explanation:

We have the following relation

$\frac{\pi }{2} < t$

if we apply the cosine function in the relation we get:

$cos\frac{\pi }{2}$

$-1$

the cosine of t is between 0 and -1 then (cosine t less than 0)

If we now apply cotangent function in the relation:

$cotan\frac{\pi }{2}$

$0$

This means that cotang is greater than 0, therefore the correct answer is b. cosine t less than 0 and cotangent t greater than 0

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Shtirlitz [24]

9514 1404 393

Answer:

15/17

Step-by-step explanation:

cos(arctan(8/15)) = 15/17

You could assume the ratio values 8 and 15 represent the opposite and adjacent sides of a right triangle. Then the hypotenuse is ...

h = √(8² +15²) = √289 = 17

The cosine is the ratio of the adjacent side to the hypotenuse, so is ...

cos(x) = 15/17

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Alinara [238K]

Answer:

2 or maybe 11 lol

thank you for the points

;-).......

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