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3 years ago

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Joel has an MP3 player called the Jumble. The Jumble randomly selects a song for the user to listen to. Joel's Jumble has 222 cl

assical songs, 131313 rock songs, and 555 rap songs on it.
What is \text{P(rock song or rap song})P(rock song or rap song)start text, P, left parenthesis, r, o, c, k, space, s, o, n, g, space, o, r, space, r, a, p, space, s, o, n, g, end text, right parenthesis?

1 answer:

mash [69]3 years ago

7 0

ANSWER

0.9

Step-by-step explanation:

no.of favourable outcome/no.of.possible outcome

13+5=18 favourable outcome and 20 possible outcome 18/20=0.9

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A man spent 58% of his income and the amount of money left was $210. Find his income

professor190 [17]

Answer:

500 $

Step-by-step explanation:

$\frac{42\%}{210}=\frac{100\%}{x}$

$\frac{\frac{21}{50}}{210}=\frac{1}{x}$

$\frac{21}{50}x=210\\$

$\frac{21}{50}x\cdot \:50=210\cdot \:50\\$

x=500

<3

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3 years ago

What is the equation of the line that passes through the point (6,-3) and has a slope of -2/3?

prohojiy [21]

Answer:

y = -2/3x + 1

Step-by-step explanation:

Put -2/3x + 1 into y= on the graphing calculator and the point (6,-3) is in the table.

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3 years ago

Please help me with this!!

bearhunter [10]

Answer:

8.06

Step-by-step explanation:

Use the Pythagorean theorem:

$a^{2} +b^{2} =c^{2}$

The hypotenuse is always the slanted side, or c (x in this picture), but the other numbers can be interchanged. Doesn't matter.

Plug the numbers 4 and 7 into the formula.

$4^{2} +7^{2} =c^{2} \\$

Now evaluate them to get $c^2$

16+49=65

To get c, take the square root of 65

$\sqrt{65} = 8.06$

6 0

3 years ago

The coordinates of the vertices of triangle ABC are A(3,6), B(6, 3), and C(9, 9). If triangle ABC Is dilated by 1/3x and 1/3y to

katovenus [111]

Answer:

$A' = (1,2)$

$B'=(2,1)$

$C' =(3,3)$

Step-by-step explanation:

Given

$A = (3,6)$

$B = (6,3)$

$C = (9,9)$

$Scale = \frac{1}{3}$

Required

Determine the vertices of ABC

If truly the question asks for the vertices of ABC, then the vertices are:

$A = (3,6)$ $B = (6,3)$ $C = (9,9)$

However, I'm quite sure that's not the requirement of the question. So, I'll solve for A'B'C'

To do this, we simply multiply the vertices of ABC by the scale of dilation.

$(A'B'C') = Scale\ Factor * (ABC)$

$A' = \frac{1}{3} * A$

$A' = \frac{1}{3} * (3,6)$

$A' = (\frac{3}{3},\frac{6}{3})$

$A' = (1,2)$

$B' = \frac{1}{3} * B$

$B' = \frac{1}{3} * (6,3)$

$B' = (\frac{6}{3},\frac{3}{3})$

$B'=(2,1)$

$C' = \frac{1}{3} * C$

$C' = \frac{1}{3} * (9,9)$

$C' = (\frac{9}{3},\frac{9}{3})$

$C' =(3,3)$

6 0

3 years ago

Two number cubes are rolled for two separate events:

MatroZZZ [7]

Let us first make the sample space for the event A. The Sample Space will be:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5)

(5,1) (5,2) (5,3) (5,4)

(6,1) (6,2) (6,3)

As can be clearly seen the Sample Space for the event A has 30 elements in it.

Now, it is given in the question that the event A has already occurred and we need to find the probability of the event B occurring <u><em>given that the event A has already occurred.</em></u>

Now, as we can see, from the sample space, only 11 events out of the 30 are the events of interest to us. This is shown in bold below:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5)

(5,1) (5,2) (5,3) (5,4)

(6,1) (6,2) (6,3)

Thus, the probability that the event B occurs given that the event A has already occurred is:

$P(B|A)=\frac{11}{30}\approx0.367$

In percentage the required probability is 36.7% approximately.

3 0

3 years ago