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Inessa [10]
3 years ago
10

One grocery store sells 8 pounds of bananas for $3.12. Another grocery store sells 9 pounds of bananas for $3.06.

Mathematics
2 answers:
drek231 [11]3 years ago
5 0

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

Number of pounds = 8

Cost of bananas = $3.12

Unit rate would be \dfrac{3.12}{8}=\$0.39

Number of pounds = 9

Cost of bananas = $3.06

Unit rate would be \dfrac{3.06}{9}=\$0.34

Difference between two unit rates would be

\$0.39-\$0.34\\\\=\$0.05

so, the rate for the first store is $0.05 per pound more than the second store.

Hence, Third option is correct.

lesantik [10]3 years ago
4 0

Answer:

the 3rd one

Step-by-step explanation:

$3.12÷8=$0.39

$3.06÷9=$0.34

$0.39 is 0.05 more than $0.34

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The midpoint of PQ is M(, –1). One endpoint is Q(3, –5). Which equations can be solved to determine the coordinates of P? Check
valkas [14]

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3 years ago
Mukat has five times as many book as usha.If mukat gave 16 books to usha,they each would have the same number.how many books did
vladimir1956 [14]

Mukat gets 40, Usha gets 8

Step-by-step explanation:

Mukat = 5 × Usha

After Mukat gives Usha 16 books ,Usha gets (16 + initial number of books) and Mukat gets (5 × Usha - 16)

Then Mukat = final number of books for Usha

5 × Usha - 16 = Usha + 16

(5 × Usha ) - Usha = 16+16

4 × Usha = 32

Usha = 8 i.e her number of books.

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I HOPE IT'S OK

6 0
3 years ago
Answer fast its sue by end of class
shtirl [24]

Step-by-step explanation:

question 1. Solve the equation 8-7/10 c = 6 - 1/5c for c

8 - 7/10c = 6 - 1/5c

subtract 8 from both sides:

8 - 7/10c - 8 = 6 - 1/5c - 8

- 7/10c  = -2 - 1/5c

add 1/5c to both sides:

- 7/10c + 1/5c = -2 - 1/5c  + 1/5c

- 7/10c + 1/5c = -2

change to common denominator:

- 7/10c+ 2/10c = -2

- 5/10c = -2

-1/2c = -2

multiply both sides by -2:

- 1/2c(-2) = -2(-2)

c = 4

___________________________________

question 2. 75 - 3.5y - 4y = 4y + 6 for y

75 - 3.5y - 4y = 4y + 6

75 - 7.5y = 4y + 6

add 7.5y to both sides:

75 - 7.5y + 7.5y = 4y + 6 + 7.5y

75 = 11.5y + 6

subtract 6 from both sides:

75 - 6 = 11.5y + 6 - 6

69 = 11.5y

divide both sides by 11.5:

69/11.5 = 11.5y/11.5

y = 6

___________________________________

Question 3. Solve the equation 16.5 + 2.75h = 9h + 7.5 − 4.25h for h.

16.5 + 2.75h = 9h + 7.5 − 4.25h

16.5 + 2.75h = 4.75h + 7.5

subtract 7.5 from both sides:

16.5 + 2.75h - 7.5 = 4.75h + 7.5 - 7.5

9 + 2.75h =  4.75h

subtract 2.75h from both sides:

9 + 2.75h - 2.75h =  4.75h - 2.75h

9 = 2h

divide both sides by 2:

9/2 = 2h/2

h = 9/2

6 0
1 year ago
The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.3 minutes and a standard deviation of 3.3
In-s [12.5K]

Answer:

a) There is a 74.22% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

b) There is a 1-0.0548 = 0.9452 = 94.52% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

c) There is a 68.74% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.3 minutes and a standard deviation of 3.3 minutes. This means that \mu = 8.3, \sigma = 3.3.

(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes?

We are working with a sample mean of 37 jets. So we have that:

s = \frac{3.3}{\sqrt{37}} = 0.5425

Total time of 320 minutes for 37 jets, so

X = \frac{320}{37} = 8.65

This probability is the pvalue of Z when X = 8.65. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.65 - 8.3}{0.5425}

Z = 0.65

Z = 0.65 has a pvalue of 0.7422. This means that there is a 74.22% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes?

Total time of 275 minutes for 37 jets, so

X = \frac{275}{37} = 7.43

This probability is subtracted by the pvalue of Z when X = 7.43

Z = \frac{X - \mu}{\sigma}

Z = \frac{7.43 - 8.3}{0.5425}

Z = -1.60

Z = -1.60 has a pvalue of 0.0548.

There is a 1-0.0548 = 0.9452 = 94.52% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes?

Total time of 320 minutes for 37 jets, so

X = \frac{320}{37} = 8.65

Total time of 275 minutes for 37 jets, so

X = \frac{275}{37} = 7.43

This probability is the pvalue of Z when X = 8.65 subtracted by the pvalue of Z when X = 7.43.

So:

From a), we have that for X = 8.65, we have Z = 0.65, that has a pvalue of 0.7422.

From b), we have that for X = 7.43, we have Z = -1.60, that has a pvalue of 0.0548.

So there is a 0.7422 - 0.0548 = 0.6874 = 68.74% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes.

7 0
3 years ago
Help please!!! I only have 10 minutes!!
goblinko [34]
I think 0.7 would be it
3 0
2 years ago
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