3 years ago

Can somebody help me with the problem attached. It is on simplifying rational expressions. Thanks!

Mathematics

1 answer:

liq [111]3 years ago

3 0

The answer is 8 as in eight

You might be interested in

Find real solutions x-(4-8x)^0.5=0

Vadim26 [7]

Answer:

There are no real roots for this equation.

Step-by-step explanation:

The only solution is irrational: x-√(4-8x)=0

I have provided a graph to help you with this problem.

Hope this helps! :)

5 0

3 years ago

When Elyse moved last weekend, the circular glass top for an end table broke. To replace it, she bought a circular glass top wit

spin [16.1K]

Answer:

Step-by-step explanation:

hmu for an explanation

4 0

3 years ago

Read 2 more answers

in 2005, musicmart sold 12,000 cds. in 2010, they sold 14,550 cds. what is the rate of change in the number of cds sold?

inn [45]

2010-2005= 5 years. 14550-12000=2550
2550/5 = ans = 510 cds/year

8 0

2 years ago

Given AB = 18, DE = 6, and AD = 5, find<br> the perimeter of ADEF<br> Perimeter =?

anygoal [31]

Answer:

this is my other accont

Step-by-step explanation:

4 0

3 years ago

Question 2b only! Evaluate using the definition of the definite integral(that means using the limit of a Riemann sum

lara [203]

Answer:

Hello,

Step-by-step explanation:

We divide the interval [a b] in n equal parts.

$\Delta x=\dfrac{b-a}{n} \\\\x_i=a+\Delta x *i \ for\ i=1\ to\ n\\\\y_i=x_i^2=(a+\Delta x *i)^2=a^2+(\Delta x *i)^2+2*a*\Delta x *i\\\\\\Area\ of\ i^{th} \ rectangle=R(x_i)=\Delta x * y_i\\$

$\displaystyle \sum_{i=1}^{n} R(x_i)=\dfrac{b-a}{n}*\sum_{i=1}^{n}\ (a^2 +(\dfrac{b-a}{n})^2*i^2+2*a*\dfrac{b-a}{n}*i)\\$

$=(b-a)^2*a^2+(\dfrac{b-a}{n})^3*\dfrac{n(n+1)(2n+1)}{6} +2*a*(\dfrac{b-a}{n})^2*\dfrac{n (n+1)} {2} \\\\\displaystyle \int\limits^a_b {x^2} \, dx = \lim_{n \to \infty} \sum_{i=1}^{n} R(x_i)\\\\=(b-a)*a^2+\dfrac{(b-a)^3 }{3} +a(b-a)^2\\\\=a^2b-a^3+\dfrac{1}{3} (b^3-3ab^2+3a^2b-a^3)+a^3+ab^2-2a^2b\\\\=\dfrac{b^3}{3}-ab^2+ab^2+a^2b+a^2b-2a^2b-\dfrac{a^3}{3} \\\\\\\boxed{\int\limits^a_b {x^2} \, dx =\dfrac{b^3}{3} -\dfrac{a^3}{3}}\\$

4 0

2 years ago