Answer:
A=(16 -5 0 -9)-(3 -4 -11 24)
Step-by-step explanation:
The solution process for any algebraic expression is to "undo" what is done to the variable. Here, matrix A has (3 -4 -11 24) added to it. The next step is to undo that addition, by subtracting that amount from both sides of the equation. The result is ...
A = (16 -5 0 -9)-(3 -4 -11 24)
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We assume there are typos in the answer choices listed here.
Step-by-step explanation:
{2,3,5,7,9,11,13,15,17,19}
36! goodluck hope it good
I got D.
There's a few ways to solve it; I prefer using tables, but there are functions on a TI-84 that'll do it for you too. The logic here is, you have a standard normal distribution which means right away, the mean is 0 and the standard deviation is 1. This means you can use a Z table that helps you calculate the area beneath a normal curve for a range of values. Here, your two Z scores are -1.21 and .84. You might notice that this table doesn't account for negative values, but the cool thing about a normal distribution is that we can assume symmetry, so you can just look for 1.21 and call it good. The actual calculation here is:
1 - Z-score of 1.21 - Z-score .84 ... use the table or calculator
1 - .1131 - .2005 = .6864
Because this table calculates areas to the RIGHT of the mean, you have to play around with it a little to get the bit in the middle that your graph asks for. You subtract from 1 to make sure you're getting the area in the middle and not the area of the tails in this problem.