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konstantin123 [22]
3 years ago
11

Which strategy can be used to solve this problem? The surface area of a cube is 24 square inches. What is the perimeter of one o

f the faces of the cube?
Mathematics
1 answer:
Anna71 [15]3 years ago
8 0
150 square inches or 150 in^2
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What is the volume of a container with sides 1ft, 2ft, and 2.5 ft
almond37 [142]

Answer:

5ft^3

Step-by-step explanation:

The formula for volume is length × width × height.

so you multiply 1×2×2.5, which equals 5

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35.00 (each). You have a coupon for %10 off . How much is the total cost with the discount ?
nata0808 [166]

Answer:

$31.50

Step-by-step explanation:

35-10%=31.5


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A wheel has a diameter of 16 inches. How far will the wheel travel after 1 rotation?
timurjin [86]

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Step-by-step explanation:

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3 years ago
Suppose that 60 batteries are shipped to an auto parts store, and that 5 of those are defective. A fleet manager then buys 6 of
PIT_PIT [208]

Answer:

In 8910 ways can at least 4 defective batteries be included in the purchase

Step-by-step explanation:

The order in which the batteries are there is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

4 defective:

4 defective from a set of 5 and 2 non-defective from a set of 60 - 5 = 55. So

C_{5,4}C_{60,2} = \frac{5!}{1!4!} \times \frac{60!}{2!58!} = 8850

5 defective:

5 defective from a set of 5 and 1 non-defective from a set of 60 - 5 = 55. So

C_{5,5}C_{60,5} = \frac{5!}{0!5!} \times \frac{60!}{1!59!} = 60

In how many ways can at least 4 defective batteries be included in the purchase?

T = 8850 + 60 = 8910

In 8910 ways can at least 4 defective batteries be included in the purchase

8 0
3 years ago
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