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3 years ago

For which value of x is the equation 4x + 24 = 8x + 2x true?

Mathematics

1 answer:

Paha777 [63]3 years ago

3 0

Answer:

x=4

Step-by-step explanation:

4x+24=8x+2x

4x+24=10x

-4x -4x

24=6x

/6 /6

x=4

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Four buses carrying 146 high school students arrive to Montreal. The buses carry, respectively, 32, 44, 28, and 42 students. One

Naily [24]

Answer:

The expected value of X is $E(X)=\frac{2754}{73} \approx 37.73$ and the variance of X is $Var(X)=\frac{226192}{5329} \approx 42.45$

The expected value of Y is $E(Y)=\frac{73}{2} \approx 36.5$ and the variance of Y is $Var(Y)=\frac{179}{4} \approx 44.75$

Step-by-step explanation:

(a) Let X be a discrete random variable with set of possible values D and probability mass function p(x). The expected value, denoted by E(X) or $\mu_x$ , is

$E(X)=\sum_{x\in D} x\cdot p(x)$

The probability mass function $p_{X}(x)$ of X is given by

$p_{X}(28)=\frac{28}{146} \\\\p_{X}(32)=\frac{32}{146} \\\\p_{X}(42)=\frac{42}{146} \\\\p_{X}(44)=\frac{44}{146}$

Since the bus driver is equally likely to drive any of the 4 buses, the probability mass function $p_{Y}(x)$ of Y is given by

$p_{Y}(28)=p_{Y}(32)=p_{Y}(42)=p_{Y}(44)=\frac{1}{4}$

The expected value of X is

$E(X)=\sum_{x\in [28,32,42,44]} x\cdot p_{X}(x)$

$E(X)=28\cdot \frac{28}{146}+32\cdot \frac{32}{146} +42\cdot \frac{42}{146} +44 \cdot \frac{44}{146}\\\\E(X)=\frac{392}{73}+\frac{512}{73}+\frac{882}{73}+\frac{968}{73}\\\\E(X)=\frac{2754}{73} \approx 37.73$

The expected value of Y is

$E(Y)=\sum_{x\in [28,32,42,44]} x\cdot p_{Y}(x)$

$E(Y)=28\cdot \frac{1}{4}+32\cdot \frac{1}{4} +42\cdot \frac{1}{4} +44 \cdot \frac{1}{4}\\\\E(Y)=146\cdot \frac{1}{4}\\\\E(Y)=\frac{73}{2} \approx 36.5$

(b) Let X have probability mass function p(x) and expected value E(X). Then the variance of X, denoted by V(X), is

$V(X)=\sum_{x\in D} (x-\mu)^2\cdot p(x)=E(X^2)-[E(X)]^2$

The variance of X is

$E(X^2)=\sum_{x\in [28,32,42,44]} x^2\cdot p_{X}(x)$

$E(X^2)=28^2\cdot \frac{28}{146}+32^2\cdot \frac{32}{146} +42^2\cdot \frac{42}{146} +44^2 \cdot \frac{44}{146}\\\\E(X^2)=\frac{10976}{73}+\frac{16384}{73}+\frac{37044}{73}+\frac{42592}{73}\\\\E(X^2)=\frac{106996}{73}$

$Var(X)=E(X^2)-(E(X))^2\\\\Var(X)=\frac{106996}{73}-(\frac{2754}{73})^2\\\\Var(X)=\frac{106996}{73}-\frac{7584516}{5329}\\\\Var(X)=\frac{7810708}{5329}-\frac{7584516}{5329}\\\\Var(X)=\frac{226192}{5329} \approx 42.45$

The variance of Y is

$E(Y^2)=\sum_{x\in [28,32,42,44]} x^2\cdot p_{Y}(x)$

$E(Y^2)=28^2\cdot \frac{1}{4}+32^2\cdot \frac{1}{4} +42^2\cdot \frac{1}{4} +44^2 \cdot \frac{1}{4}\\\\E(Y^2)=196+256+441+484\\\\E(Y^2)=1377$

$Var(Y)=E(Y^2)-(E(Y))^2\\\\Var(Y)=1377-(\frac{73}{2})^2\\\\Var(Y)=1377-\frac{5329}{4}\\\\Var(Y)=\frac{179}{4} \approx 44.75$

8 0

3 years ago

Its a word problem in algebra 1 that i need help on step by step ?

Luden [163]

Answer:

Cost of one rose bush = $2 and cost of 1 geranium = $11

Step-by-step explanation:

lets assume cost of one rose bush = $x

lets assume cost of one geranium = $y

Given that Norachai spent $13 on 1 rose and 1 geranium

⇒ 1 × (cost of one rose bush) + 1× (cost of one geranium) = 13

⇒ 1x + 1y = 13 ----------------------------equation 1

Also given that Castel spent $46 on 1 rose bush and 4 geraniums

⇒1 × (cost of one rose bush) + 4× (cost of one geranium) = 46

⇒ 1x + 4y = 46 ----------------------------equation 2

Now we are having following two equations which will be used to find the value of x and y

1x + 1y = 13 ----------------------------equation 1

1x + 4y = 46 ----------------------------equation 2

lets modify equation 1 to get value of y in terms of x and name that equation as equation 3

1x + 1y = 13 ----------------------------equation 1

⇒ y = 13 - x -----------------------------equation 3

On substituting value of y from equation 3 in equation 2 we get

1x + 4 × ( 13 - x ) = 46

⇒ x + 52-4x =46

⇒ -3x = 46-52

⇒ x = (-6)/(-3) = 2

on substituting calculated value of x that is 2 in equation 3 we get

y = 13 -2 = 11

so on solving the equations we get x = 2 and y = 11.

Hence cost of 1 rose bush = $x = $2 and cost of 1 geranium = $y = $11

8 0

2 years ago

State the excluded values for each? 70v^2/100v

sleet_krkn [62]

Ok so any number tat makes the denomenator 0 or makes the inside of a square root negative is restricted
we only have a denomenaor so
100v=0
v=0
therefor 0 is the excluded value since 0/0 doesn't make sense

6 0

3 years ago

.............................................................

Len [333]

Answer:

0.058863

Step-by-step explanation:

5 0

2 years ago

2(3 – 8y)

Hoochie [10]

Answer:

Step-by-step explanation:

7 0

2 years ago

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