Y = 4x - 9 and y = x-3 so the two right sides (4x-9 and x-3) must be equal

4x-9 = x-3

Let's solve for x

4x-9 = x-3
4x-9+9 = x-3+9 ... add 9 to both sides
4x = x+6
4x-x = x+6-x ... subtract x from both sides
3x = 6
3x/3 = 6/3 ... divide both sides by 3
x = 2

If x = 2, then y is...
y = 4*x - 9 = 4*2-9 = 8-9 = -1
which can also be found by
y = x-3 = 2-3 = -1

So overall x = 2 and y = -1

We have the ordered pair (x,y) = (2,-1)

4 0

3 years ago

Section 5.2-9. Solve the following system of equations by substitution or elimination. Enter your answer as (x,y).2x+y = 2-3x-2y

Alika [10]

$\begin{gathered} (2x+y=2)\times2 \\ -3x-2y=-8 \\ 4x+2y=4 \\ -3x-2y=-8 \\ \text{subtract above two equations} \\ x=-4 \\ \text{put the value of x in equation 1st then get y} \\ 4(-4)+2y=4 \\ -16+2y=4 \\ 2y=20 \\ y=10 \\ (x,y)=(-4,10) \end{gathered}$

6 0

1 year ago

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