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Akimi4 [234]
3 years ago
10

What is the value of x for this question?

Mathematics
1 answer:
cestrela7 [59]3 years ago
4 0

Answer:

Step-by-step explanation:

3x + 3

6 + 2x

3x + 2x = 5x

3 + 6 = 9

5x + 9

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Fourth degree and a single zero of -3
Darya [45]

The degree of a polynomial is the highest power of the polynomial.

The polynomial is \mathbf{P(x) = (x + 3)^4}

The degree is given as:

\mathbf{n = 4}

The zero is given as:

\mathbf{x = -3}

Add 3 to both sides

\mathbf{x  + 3= 0}

From the question, we understand that the polynomial has a single zero.

So, the polynomial is:

\mathbf{P(x) = (x + 3)^n}

Substitute 4 for n

\mathbf{P(x) = (x + 3)^4}

Hence, the polynomial is \mathbf{P(x) = (x + 3)^4}

Read more about polynomials at:

brainly.com/question/11536910

3 0
3 years ago
SOMEBODY HELP MEEE!!!!
VladimirAG [237]
Solution= x=5
Alernative form= 21 x - 105= 0<span />
8 0
3 years ago
Can someone help me pls
NikAS [45]

Answer:

Step-by-step explanation:

what do you want me to do???

just tell me what to do

8 0
3 years ago
g A manufacturer is making cylindrical cans that hold 300 cm3. The dimensions of the can are not mandated, so to save manufactur
sdas [7]

Answer:

The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

Step-by-step explanation:

A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.

Recall that the volume for a cylinder is given by:

\displaystyle V = \pi r^2h

Substitute:

\displaystyle (300) = \pi r^2 h

Solve for <em>h: </em>

\displaystyle \frac{300}{\pi r^2} = h

Recall that the surface area of a cylinder is given by:

\displaystyle A = 2\pi r^2 + 2\pi rh

We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.

First, substitute for <em>h</em>.

\displaystyle \begin{aligned} A &= 2\pi r^2 + 2\pi r\left(\frac{300}{\pi r^2}\right) \\ \\ &=2\pi r^2 + \frac{600}{ r}  \end{aligned}

Find its derivative:

\displaystyle A' = 4\pi r - \frac{600}{r^2}

Solve for its zero(s):

\displaystyle \begin{aligned} (0) &= 4\pi r  - \frac{600}{r^2} \\ \\ 4\pi r - \frac{600}{r^2} &= 0 \\ \\ 4\pi r^3 - 600 &= 0 \\ \\ \pi r^3 &= 150 \\ \\ r &= \sqrt[3]{\frac{150}{\pi}} \approx 3.628\text{ cm}\end{aligned}

Hence, the radius that minimizes the surface area will be about 3.628 centimeters.

Then the height will be:

\displaystyle  \begin{aligned} h&= \frac{300}{\pi\left( \sqrt[3]{\dfrac{150}{\pi}}\right)^2}  \\ \\ &= \frac{60}{\pi \sqrt[3]{\dfrac{180}{\pi^2}}}\approx 7.25 6\text{ cm}   \end{aligned}

In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

7 0
3 years ago
Provide a radian measure of an angle that is 5/8 of a revolution counterclockwise from the x-axis.
tia_tia [17]
I’m pretty sure but not so sure I think it is 180
5 0
2 years ago
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