Answer: False
Step-by-step explanation: Absolute value means <em>distance from zero</em> on a number line. A common mistake is to assume that absolute value is always positive but that's not necessarily the case.
Take 0 for example.
It's 0 units away from zero on a number line which
means it has an absolute value of zero.
However, all other numbers besides zero will have
an absolute value that is positive.
Answer:
$78, $79.20
Step-by-step explanation:
PART A: $60 times 1.3 = $78
you add 30% to 100% to get 130% since it is a mark up, and then you convert to a decimal by going to the left twice then multiplying by original price.
PART B
Since it is a discount you subtract 15 percent from 100, but then add back 5 percent since there is tax applied to get 90%, convert to decimal and multiply by original price to get $88 x .9 = $79.20
Answer:
520 feet
Step-by-step explanation:
The easiest way to visualize this problem is to sketch a quick diagram.
For this problem, you are given an angle and the length of the side of a triangle. If you look at the diagram, you'll see that the length given is the opposite side of the angle given. For this situation, that means you will use the sine function (refer to SOH-CAH-TOA acronym). Then you plug in the given values and solve for x.
Hope this helps!
Answer:
$43.35 (I believe)
Step-by-step explanation:
I tried to find the price to fill up 1 gallon by dividing the $30.60 by 12. 30.6/12 = 2.55 and then I multiplied $2.55 by 17 and got $43.35
Answer:
A. y = –5x – 27
Step-by-step explanation:
Find the slope of the original line and use the point-slope formula y
−
y
1
=
m
(
x
−
x
1
) to find the line parallel to y
=
−
5
x
+
3
.
y
=
−
5
x
−
27 PARALLEL
...................................................................................................................................................
Find the negative reciprocal of the slope of the original line and use the point-slope formula y
−
y
1
=
m
(
x
−
x
1
) to find the line perpendicular to y
=
−
5
x
+
3
.
y
=
1
/5
x
+
21
/5 PERPENDICULAR
