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BartSMP [9]
3 years ago
13

Solve the equation show you work and check. Your answer 4y+5=31

Mathematics
2 answers:
Lesechka [4]3 years ago
8 0
To find y, which is what I believe you mean by solving the equation, you have to first subtract 5 from each side. You'll have

4y=26

Then you have to divide each side by 4. Then you will get

y= 6.5

taurus [48]3 years ago
3 0
31-5=26
26/4=6.5
Y=6.5

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Trying to help my daughter can't figure this out.
Anvisha [2.4K]

Answer:

width equals 16

length = 20

Step-by-step explanation:

Hello there!

we know that the perimeter is 72 m

and the width is 4 m less then the length

perimeter is 2w+2l

w=width and l = length

72 + (2x-4) = 72+8 = 80

80 / 4 (because there are 4 values, w, w, l, l ) = 20

so now...

20 - 4 = w

16 = w

and 20 = l

16+16 = 32

20+20 = 40

32+40 = 72

7 0
3 years ago
A professor compares the number of students at his school majoring in statistics, engineering, both, or neither.
Ymorist [56]

Answer:

Step-by-step explanation:

3

5 0
3 years ago
An internet search engine looks for a certain keyword in a sequence of independent web sites. It is believed that 20% of the sit
marusya05 [52]

Answer:

(a) The probability that at least 5 of the first 10 sites contain the given keyword is 0.0328.

(b) The probability that the search engine had to visit at least 5 sites in order to find the first occurrence of a keyword is 0.4096.

Step-by-step explanation:

(a)

Let <em>X</em> = number of sites that contains the keyword.

The probability that a site contains the keyword is, <em>p</em> = 0.20.

The number of sites visited first is <em>n</em> = 10.

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={10\choose x}0.20^{x}(1-0.20)^{10-x};\ x=0,1,2,3...

Compute the probability that at least 5 of the first 10 sites contain the given keyword as follows:

P (X ≥ 5) = 1 - P (X < 5)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3) - P (X = 4)

              =1-\sum\limits^{4}_{x=0} {10\choose x}0.20^{x}(1-0.20)^{10-x}\\=1-0.1074-0.2684-0.3020-0.2013-0.0881\\=0.0328

Thus, the probability that at least 5 of the first 10 sites contain the given keyword is 0.0328.

(b)

Let <em>Y</em> = number of sites that contains the keyword.

The probability that a site contains the keyword is, <em>p</em> = 0.20.

The random variable <em>Y</em> follows a Geometric distribution with parameter <em>p</em>.

The probability mass function of <em>Y</em> is:

P(Y=y)=(1-p)^{x-1}p;\ x=1,2,3...

Compute the probability that the search engine had to visit at least 5 sites in order to find the first occurrence of a keyword as follows:

P (X ≥ 5) = 1 - P (X ≤ 4)

             =1-\sum\limits^{4}_{x=1} (1-0.20)^{x-1}0.20\\=1-0.20-0.16-0.128-0.1024\\=0.4096

Thus, the probability that the search engine had to visit at least 5 sites in order to find the first occurrence of a keyword is 0.4096.

4 0
4 years ago
<img src="https://tex.z-dn.net/?f=y%2B6%3D15" id="TexFormula1" title="y+6=15" alt="y+6=15" align="absmiddle" class="latex-formul
Ne4ueva [31]

Answer:

y = 9

Step-by-step explanation:

y + 6 = 15

y = 15 - 6

\boxed{\green{y = 9 }}

7 0
3 years ago
Read 2 more answers
Can you solve (4x-3)/(x+2)+(15)/(x-3)
Murljashka [212]
Please see the pic, I'd solved in it.

8 0
3 years ago
Read 2 more answers
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