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2 years ago

What is $59.99 with 15% off

1 answer:

8 0

First you turn 15% into a decimal by dividing by 100
.15 then multiply by 59.99 and get around 8.99
Then subtract 8.99 from 59.99 and get $51
So $59.99 with 15% off is about $51

Hope this helped! :))

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Morgan is walking her dog on an 8-meter-long leash. She is currently 500 meters from her house, so the maximum and minimum dista

Gnom [1K]

Given:
Morgan = 500 meters from her house
Length of leash = 8 meters

minimum distance of the dog from the house 500 - 8 = 492 meters.
maximum distance of the dog from the house 500 + 8 = 508 meters.

7 0

3 years ago

Prove the following by induction. In each case, n is apositive integer. 2^n ≤ 2^n+1 - 2^n-1 -1.

frutty [35]

<h2>Answer with explanation:</h2>

We are asked to prove by the method of mathematical induction that:

$2^n\leq 2^{n+1}-2^{n-1}-1$

where n is a positive integer.

Let us take n=1

then we have:

$2^1\leq 2^{1+1}-2^{1-1}-1\\\\i.e.\\\\2\leq 2^2-2^{0}-1\\\\i.e.\\2\leq 4-1-1\\\\i.e.\\\\2\leq 4-2\\\\i.e.\\\\2\leq 2$

Hence, the result is true for n=1.

Let us assume that the result is true for n=k

i.e.

$2^k\leq 2^{k+1}-2^{k-1}-1$

Now, we have to prove the result for n=k+1

i.e.

To prove: $2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1$

Let us take n=k+1

Hence, we have:

$2^{k+1}=2^k\cdot 2\\\\i.e.\\\\2^{k+1}\leq 2\cdot (2^{k+1}-2^{k-1}-1)$

( Since, the result was true for n=k )

Hence, we have:

$2^{k+1}\leq 2^{k+1}\cdot 2-2^{k-1}\cdot 2-2\cdot 1\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{k-1+1}-2\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-2$

Also, we know that:

$-2$

(

Since, for n=k+1 being a positive integer we have:

$2^{(k+1)+1}-2^{(k+1)-1}>0$ )

Hence, we have finally,

$2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1$

Hence, the result holds true for n=k+1

Hence, we may infer that the result is true for all n belonging to positive integer.

i.e.

$2^n\leq 2^{n+1}-2^{n-1}-1$ where n is a positive integer.

6 0

3 years ago

What is the surface area of the box?

jonny [76]

1700 because I multiply 30 x 20 then 20 x 5 then 30 x 5 then add them all up and multiply your answer by 2

3 0

2 years ago

Read 2 more answers

Find two additional roots of P(x)=0. 13+sqrt 3 and 7i

vova2212 [387]

So, x = 13, x = √3 and x =7i.

now, recall that for an EVEN radical, there are two possible roots, namely is say √3 is say hmmm some value "a", that means that a*a = √3, however, -a*-a is also √3, therefore, ±√3 are two valid values, and therefore -√3 is another one.

now.... keep in mind that, complex solutions or roots, never come all by their lonesome, their sister is always with them, the conjugate, so, for 7i or namely 0 + 7i, her sister is always around, 0 - 7i, which is the other root.

4 0

3 years ago

-2x - 5y = 13 2x - 5y =17

Flura [38]

{-2x-5y=13

{2x-5y=17 (+)

-2x+2x-5y-5y=13+17

-10y=30 /:(-10)

y=-3

2x-5y=17

2x-5*(-3)=17

2x+15=17

2x=2

x=1

Solution: (1; -3)

6 0

2 years ago