Answer:
a) 151lb.
b) 6.25 lb
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean 
and standard deviation 
, a large sample size can be approximated to a normal distribution with mean and standard deviation 
.
In this problem, we have that:
So
a) The expected value of the sample mean of the weights is 151 lb.
(b) What is the standard deviation of the sampling distribution of the sample mean weight?
This is 
Answer:
Step-by-step explanation:
Given that the dresser is in shape of a rectangular prism
Note that, a rectangular prism has a shape of a cuboid
So, area of the rectangular prism is same as area of a cuboid
A = (2LB + 2LH + 2BH)
Where
L is length
B is breadth
H is height
Then, given the dimension of the rectangular prism to be
2ft by 2ft by 6ft
Then, you can assume that,
Length L = 2ft
Breadth B = 2ft
Height H = 6ft.
NOTE: you can take you assumption anyhow, there is no standard, you will get the same answer.
Then,
A = (2LB + 2LH + 2BH)
A = (2×2×2 + 2×2×6 + 2×2×6)
A = (8 + 24 + 24)
A = 56 ft²
The total surface area of the dresser is 56ft²
104 and 105 are consecutive numbers that add up to 209. Maybe this answers your question? Let me know otherwise.
