Answer: x=r^2
+
10
r
+
25
(a) The probability of drawing a blue marble at random from a given box is the number of blue marbles divided by the total number of marbles. We assume that the probability of selecting one of two boxes at random is 1/2 for each box.
... P(blue) = P(blue | box1)·P(box1) + P(blue | box2)·P(box2) = (3/8)·(1/2) + (4/6)·(1/2)
... P(blue) = 25/48 . . . . probability the ball is blue
(b) P(box1 | blue) = P(blue & box1)/P(blue) = (P(blue | box1)·P(box1)/P(blue)
... = ((3/8)·(1/2))/(25/48)
... P(box1 | blue) = 9/25 . . . . probability a blue ball is from box 1
No, to find the least number of burgers and buns, you should find out the LCM of 15 and 6, not their product.
LCM = 30,
so they need to buy atleast 30 of each item.
The five numbers can be represented by (2n+1), (2n+3), (2n+5), (2n+7), and (2n+9), where n is an integer.
<span>2n+9 = 15 </span>
<span>n = 3 </span>
<span>The third number is 2n+5 = 11</span>
