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3 years ago

Simplify 7 square root of 3 end root minus 4 square root of 6 end root plus square root of 48 end root minus square root of 54

1 answer:

3 0

$7\sqrt3-4\sqrt6+\sqrt{48}-\sqrt{54}\\\\=7\sqrt3-4\sqrt6+\sqrt{16\cdot3}-\sqrt{9\cdot6}\\\\=7\sqrt3-4\sqrt6+\sqrt{16}\cdot\sqrt3-\sqrt9\cdot\sqrt6\\\\=7\sqrt3-4\sqrt6+4\sqrt3-3\sqrt6\\\\=\boxed{11\sqrt3-7\sqrt6}$

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A scientist is studying the population growth rates of two different species of rats in the same laboratory conditions. The popu

Korolek [52]

Since, population of species A is represented by : $P=2^{x} +19$

Let us find the population of species A, at the end of week 1:

i.e., x = 1

i.e., $P(1)=2^{1} +19$

i.e., $P(1)=2 +19$

i.e., $P(1)=21$

Also, since population of species B is represented by : $P=3^{x} +18$

Let us find the population of species B, at the end of week 1:

i.e., x = 1

i.e., $P(1)=3^{1} +18$

i.e., $P(1)=3 +18$

i.e., $P(1)=21$

Thus, at the end of 1 week, species A and species B will have the same population.

Hence, option D is correct.

4 0

3 years ago

a meat pie contains chicken and turkey in the ratio 4:1. The pie contains 200g of Chicken. How much turkey is in the pie?

kogti [31]

Answer:

50 grams

Step-by-step explanation:

From the above question:

Chicken : Turkey

= 4:1

Sum Proportions = 4 + 1 = 5

We have to find the weight in grams of the entire pie

Let us represent the weight in grams of the entire pie = x.

The pie contains 200g of Chicken.

Hence:

4/5 × x = 200g

4x/5 = 200g

Cross Multiply

4x = 200g × 5

x = 200g × 5/4

x = 250g

The amount turkey that is in the pie is calculated as:

Total weight of pie - Amount of Chicken in the pie

= 250g - 200g

= 50 g

3 0

3 years ago

Solve the system of linear equations below. Enter your solution as an ordered pair (x,y). Do not include spaces in your answer..

kotykmax [81]

Y=3
4x+y=19
4x+3=19
4x=19-3
4x=16
x=4

pair is 4,3

5 0

3 years ago

Read 2 more answers

There is 2 parts. but , help

icang [17]

Answer: B

Step-by-step explanation:

6 0

2 years ago

Divide.<br> a.1 − 2i/2i<br> b. 5 − 2i/5 + 2i<br> c.√3 − 2i/−2 − √3i

Umnica [9.8K]

Answer:

(a) \frac{-1i}{2}-1[/tex]

(b) $\frac{20i+21}{29}$

Step-by-step explanation:

We have to perform division

(a) $\frac{1-2i}{2i}$

So after division

$\frac{1-2i}{2i}=\frac{1}{2i}-\frac{2i}{2i}=\frac{-1i}{2}-1$

(b) We have given expression $\frac{5-2i}{5+2i}$

After rationalizing $\frac{5-2i}{5+2i}\times \frac{5-2i}{5-2i}=\frac{(5-2i)^2}{25+4}=\frac{25+4i^2+20i}{29}=\frac{20i+21}{29}$

After rationalizing

$\frac{\sqrt{3}-2i}{-2-\sqrt{3i}}\times \frac{-2+\sqrt{3i}}{-2+\sqrt{3i}}=\frac{-2\sqrt{3}+7i+2\sqrt{3}}{7}=\frac{7i}{7}=i$

5 0

3 years ago